我正在使用cl /E ..
这是单一帖子的检查元素
lxml
对于每个这样的帖子,我想提取标题,帖子内容和发布时间。
例如上面的细节将是
<article id="post-4855" class="post-4855 post type-post status-publish format-standard hentry category-uncategorized">
<header class="entry-header">
<h1 class="entry-title"><a href="http://aitplacements.com/uncategorized/cybage/" rel="bookmark">Cybage..</a></h1>
<div class="entry-meta">
<span class="byline"> Posted by <span class="author vcard"><a class="url fn n" href="http://aitplacements.com/author/tpoait/">TPO</a></span></span><span class="posted-on"> on <a href="http://aitplacements.com/uncategorized/cybage/" rel="bookmark"><time class="entry-date published updated" datetime="2017-09-13T11:02:32+00:00">September 13, 2017</time></a></span><span class="comments-link"> with <a href="http://aitplacements.com/uncategorized/cybage/#respond">0 Comment</a></span> </div><!-- .entry-meta -->
</header><!-- .entry-header -->
<div class="entry-content">
<p>cybage placement details shared <a href="http://aitplacements.com/uncategorized/cybage/" class="read-more">READ MORE</a></p>
</div><!-- .entry-content -->
直到我能够实现的目标: 该网站需要登录,我是成功的。
用于提取信息:
{title : "Cybage..",
post : "cybage placement details shared"
datetime="2017-09-13T11:02:32+00:00"
}
raw_title给出空值headers = {'User-Agent': 'Mozilla/5.0 (X11; Linux x86_64)
Chrome/42.0.2311.90'}
url = 'http://aitplacements.com/news/'
page = requests.get(url,headers=headers)
doc = html.fromstring(page.content)
#print doc # it prints <Element html at 0x7f59c38d2260>
raw_title = doc.xpath('//h1[@class="entry-title"]/a/@href/text()')
print raw_title
?
我做错了什么?
答案 0 :(得分:0)
@href
是指href
属性的值:
In [14]: doc.xpath('//h1[@class="entry-title"]/a/@href')
Out[14]: ['http://aitplacements.com/uncategorized/cybage/']
您想要<a>
元素的文字:
In [16]: doc.xpath('//h1[@class="entry-title"]/a/text()')
Out[16]: ['Cybage..']
因此,请使用
raw_title = doc.xpath('//h1[@class="entry-title"]/a/text()')
if len(raw_title) > 0:
raw_title = raw_title[0]
else:
# handle the case of missing title
raise ValueError('Missing title')