Redshift：模式

Question

我在redshift DB中有几个架构，让我们说 sch1 和 sch2 ，并有一个名为 txn 的表格我可以访问 sch1.txn和sch2.txn

在根据以下来自redshift doc（http://docs.aws.amazon.com/redshift/latest/dg/diagnostic-queries-for-query-tuning.html#identify-tables-with-data-skew-or-unsorted-rows）的查询识别数据偏差的过程中，我无法找到列出的表 txn sch2 但仅限 sch1

SELECT trim(pgn.nspname) AS SCHEMA,
       trim(a.name) AS TABLE,
       id AS tableid,
       decode(pgc.reldiststyle,0, 'even',1,det.distkey,8,'all') AS distkey,
       dist_ratio.ratio::decimal(10,4) AS skew,
       det.head_sort AS "sortkey",
       det.n_sortkeys AS "#sks",
       b.mbytes,
       decode(b.mbytes,0,0,((b.mbytes/part.total::decimal)*100)::decimal(5,2)) AS pct_of_total,
       decode(det.max_enc,0,'n','y') AS enc,
       a.rows,
       decode(det.n_sortkeys, 0, NULL, a.unsorted_rows) AS unsorted_rows,
       decode(det.n_sortkeys, 0, NULL, decode(a.rows,0,0, (a.unsorted_rows::decimal(32)/a.rows)*100))::decimal(5,2) AS pct_unsorted
FROM
  (SELECT db_id,
          id,
          name,
          sum(ROWS) AS ROWS,
          sum(ROWS)-sum(sorted_rows) AS unsorted_rows
   FROM stv_tbl_perm a
   GROUP BY db_id,
            id,
            name) AS a
JOIN pg_class AS pgc ON pgc.oid = a.id
JOIN pg_namespace AS pgn ON pgn.oid = pgc.relnamespace
LEFT OUTER JOIN
  (SELECT tbl,
          count(*) AS mbytes
   FROM stv_blocklist
   GROUP BY tbl) b ON a.id=b.tbl
INNER JOIN
  (SELECT attrelid,
          min(CASE attisdistkey
                  WHEN 't' THEN attname
                  ELSE NULL
              END) AS "distkey",
          min(CASE attsortkeyord
                  WHEN 1 THEN attname
                  ELSE NULL
              END) AS head_sort,
          max(attsortkeyord) AS n_sortkeys,
          max(attencodingtype) AS max_enc
   FROM pg_attribute
   GROUP BY 1) AS det ON det.attrelid = a.id
INNER JOIN
  (SELECT tbl,
          max(mbytes)::decimal(32)/min(mbytes) AS ratio
   FROM
     (SELECT tbl,
             trim(name) AS name,
             slice,
             count(*) AS mbytes
      FROM svv_diskusage
      GROUP BY tbl,
               name,
               slice)
   GROUP BY tbl,
            name) AS dist_ratio ON a.id = dist_ratio.tbl
JOIN
  (SELECT sum(capacity) AS total
   FROM stv_partitions
   WHERE part_begin=0 ) AS part ON 1=1
WHERE mbytes IS NOT NULL
ORDER BY mbytes DESC;

在调试原因如下所示，我发现txn只列出一次，对应于 sch1 ，但正如我之前提到的，我可以用sch1和sch2访问它们。这非常令人困惑。

有人可以帮助我理解，如果这是模式的某些权限问题，但我也发现基于ACL，用户有权同时使用＆amp;为架构创建。

是否可以在schema ???

之间隐式链接表

rsdb=# SELECT db_id,
          id,
          name,
          sum(ROWS) AS ROWS,
          sum(ROWS)-sum(sorted_rows) AS unsorted_rows
   FROM stv_tbl_perm a where name = 'txn'
   GROUP BY db_id,
            id,
            name;
 db_id  |   id   |                                   name                                   |   rows   | unsorted_rows
--------+--------+--------------------------------------------------------------------------+----------+---------------
 100082 | 242000 | txn                                                                   | 65540000 |      65540000