{
"images": [
[
2,
"91/914fbbb8694ba1865b7bf3da0cc7ec512a0630dcf16c3f8347b6b4d3.png",
760,
3910
],
[
1,
"6c/6c9f754578229fb925cb80033cced89ff3ff56795fc50899d3718725.png",
760,
5242
],
[
0,
"44/446c0ce1047fd617ee086aaa21277229f21b0d29a753c8e3a0df8ca0.png",
760,
1080
]
]}
**需要访问Images数组中每个数组内的数据...如何将这些数据放入数组列表**
答案 0 :(得分:1)
试试这个
ArrayList<String> arrayList = new ArrayList<>();
JSONObject jsonObject= new JSONObject("response");
JSONArray myArray = jsonObject.optJSONArray("images");;
for (int j = 0; j < myArray.length(); j++) {
try {
JSONArray jsonarray = myArray.optJSONArray(j);
for (int i = 0; i < jsonarray.length(); i++){
String data = jsonarray.getString(j);
Log.e("PHOTOS_URL", i + "=" + data);
arrayList.add(data);
}
} catch (JSONException e) {
e.printStackTrace();
}
}
答案 1 :(得分:1)
假设你有jsonResponse是响应
然后SELECT ROW_NUMBER() OVER (ORDER BY rv.Timestamp DESC) AS Rows,
rv.Timestamp, c.Description, rv.Value, rv.Deltavalue, c.Tag,
(LEAD(rv.Value_num) OVER (ORDER BY rv.Timestamp) - rv.Value_num) as diff
FROM dbo.Channels c INNER JOIN
(SELECT rv.*, TRY_CONVERT(numeric(20, 4), rv.value) as value_num
FROM dbo.RecordedValues rv
) rv
ON c.SourceId = rv.SourceId AND c.SourceId = rv.ChannelId
WHERE c.Description LIKE N'%AL Electra%';
然后JSONObject jsonObject = new JSONObject(responce);
然后:
JSONArray imagejsonArray=jsonObject.optJSONArray("images");
现在对象json数组是你解析的最后一个jsonarray