Answer 1

尝试这样的事情

public IPagedList<Client> Find(int pageIndex, int pageSize)
{
    Client clientAlias = null;

    var query = Session.QueryOver<Client>(() => clientAlias)

        .Select(
            Projections.Distinct(
                Projections.ProjectionList()
                    .Add(Projections.Property<Client>(x => x.Id).As("Id"))
                    .Add(Projections.Property<Client>(x => x.Name).As("Name"))
                    .Add(Projections.Property<Client>(x => x.Surname).As("Surname"))
                    .Add(Projections.Property<Client>(x => x.GivenName).As("GivenName"))
                    .Add(Projections.Property<Client>(x => x.EmailAddress).As("EmailAddress"))
                    .Add(Projections.Property<Client>(x => x.MobilePhone).As("MobilePhone"))
            )
        )
        .TransformUsing(Transformers.AliasToBean<Client>())

        .OrderBy(() => clientAlias.Surname).Asc
        .ThenBy(() => clientAlias.GivenName).Asc;

    var count = query
        .ToRowCountQuery()
        .FutureValue<int>();

    return query
        .Take(pageSize)
        .Skip(Pagination.FirstResult(pageIndex, pageSize))
        .List<Client>()
        .ToPagedList(pageIndex, pageSize, count.Value);
}

Answer 2

我也有这个问题。首先，Distinct可以工作，但只有在调用了QueryOver.List.ToList（）方法之后，所以query.skip才能正常工作，分页重复，创建列表，然后减少我的分页数量，因为重复。

我发现最简单的事情就是......先创建一个唯一ID的列表，然后在ID自己的页面上进行分页。

然后在结果集上，您只需执行Id并仅在新分页的id结果集中检索ID。

//Create your query as usual.. apply criteria.. do what ever you want.

//Get a unique set of ids from the result set.
var idList = query.
.Select(x => x.Id)
.List<long>().Distinct().ToList();

//Do your pagination here over those ids
List<long> pagedIds = idList.Skip(0).Take(10).ToList();

//Here what used to be non distinct resultset, now is..
List<T> resultquery.Where(() => 
item.Id.IsIn(pagedIds))
.List<Person>()
.ToList();

特别感谢.. https://julianjelfs.wordpress.com/2009/04/03/nhibernate-removing-duplicates-combined-with-paging/