我想根据定义拆分基于字符串的消息。
String: AAABBB CCDDD FFGGGHHHI KKK
Definition: 2,6,3,1,6,7,rest
So,
2 AA
6 ABBB C
3 CDD
1 D
6 F
7 FGGGHHH
rest I KKK
理想情况下,如果java或spring中存在一个现有机制,它会拆分消息并实例化理想的对象。
答案 0 :(得分:2)
这正是substring所做的......
static String[] split(String source, int ... sizes){
int n = source.length(), start = 0;
String [] partials = new String[sizes.length];
for(int i = 0; i < sizes.length; i++){
int end = sizes[i] < 0 ? n : start + sizes[i];
partials[i] = source.substring(start, start = end);
}
return partials;
}
您需要做的一件事是将rest
翻译为-1
,例如:
static String[] split(String source, String sizes){
return split(source, Arrays.stream(sizes.split(","))
.mapToInt(it -> it.equals("rest") ? -1 : Integer.parseInt(it))
.toArray());
}
然后您可以使用split(String, String)
来实现自己的方式,例如:
String string = "AAABBB CCDDD FFGGGHHHI KKK";
String definition = "2,6,3,1,6,7,rest";
String[] results = split(string, definition);
// ^--- ["AA", "ABBB C", "CDD", "D", " FF", "GGGHHHI", " KKK"]
答案 1 :(得分:0)
StringBuilder temp=new StringBuilder("AAABBB CCDDD FFGGGHHHI KKK");
System.out.println(temp.substring(0,2));
temp.delete(0,2);
System.out.println(temp.substring(0,6));
temp.delete(0,6);
//it goes like this
使用StringBuilder
,每次获得子字符串,然后删除子字符串。
使用substring(int start, int end)
方法和delete(int start, int end)
答案 2 :(得分:0)
首先你在计算时出错了,这是一些代码来做你的事情:
public static void main(String[] args) {
String str = "AAABBB CCDDD FFGGGHHHI KKK";
int[] split = new int[]{2, 6, 3, 1, 6, 7};
List<String> res = new ArrayList<>();
StringBuilder temp = new StringBuilder(str);
for (int i = 0; i < split.length ; i++) {
res.add(temp.substring(0, split[i]));
temp.delete(0, split[i]);
}
res.add(temp.toString());
res.forEach(System.out::println);
}
输出是:
AA // 2
ABBB C // 6
CDD // 3
D // 1
FF // 6
GGGHHHI // 7
KKK // rest
答案 3 :(得分:0)
那是我的版本
String str = "AAABBB CCDDD FFGGGHHHI KKK";
List<Integer> def = Arrays.asList(2,6,3,1,6,7);
List<String> res = split (str, def);
int n = res.size();
for (int i = 0; i < n; i ++) {
String r = res.get(i);
if (i + 1 == n) {
System.out.println("rest: " + r);
} else {
System.out.println(r.length() + " : " + r);
}
}
public List<String> split (String pStr, List<Integer> pDef) {
List<String> ret = new ArrayList<String> ();
int startStr = 0;
int startDef = 0;
while (startStr < pStr.length() && startDef < pDef.size()) {
int end = startStr + pDef.get(startDef);
ret.add(pStr.substring(startStr, end));
startStr = end;
startDef ++;
}
if (startStr < pStr.length()) {
ret.add(pStr.substring(startStr));
}
return ret;
}
输出:
2 : AA
6 : ABBB C
3 : CDD
1 : D
6 : FF
7 : GGGHHHI
rest: KKK