Question

我收到了可怕的java.lang.IllegalArgumentException: requirement failed: The inlets [] and outlets [] must correspond to the inlets [Map.in] and outlets []错误消息，以前的SO答案对我没有帮助。

这是我的图表

val graph = RunnableGraph.fromGraph(GraphDSL.create(sink){ implicit b =>
  s =>
     import GraphDSL.Implicits._
     val broadcast = b.add(Broadcast[Foo](2))
     val merge = b.add(Merge[Foo](2))
     source ~> func1() ~> broadcast.in
     broadcast.out(0).filter(_.country == "US") ~> usSpecificFilter ~> merge.in(0)
     broadcast.out(1).filter(_.country != "US") ~> internationalFilter ~> merge.in(1)
     merge.out ~> sink
     ClosedShape
})

def func1() : Flow[String, Foo, NotUsed] = {...}

从以前的线程我可以收集到，如果你有“未使用的流”（意味着添加到构建器但未在图中使用的东西），则会出现此错误。

但正如您在上面所看到的那样，我没有未使用过的流量。

编辑::

val graph = RunnableGraph.fromGraph(GraphDSL.create(sink){ implicit b =>
  s =>
     import GraphDSL.Implicits._
     val broadcast = b.add(Broadcast[Foo](2))
     val merge = b.add(Merge[Foo](2))
     val s = b.add(sink)
     source ~> func1() ~> broadcast.in
     broadcast.out(0).filter(_.country == "US") ~> usSpecificFilter ~> merge.in(0)
     broadcast.out(1).filter(_.country != "US") ~> internationalFilter ~> merge.in(1)
     merge.out ~> s.in
     ClosedShape
})

仍然无效！

Answer 1

在图表中，将merge.out ~> sink更改为merge.out ~> s.in：

val graph = RunnableGraph.fromGraph(GraphDSL.create(sink) { implicit b => s =>
  import GraphDSL.Implicits._

  val broadcast = b.add(Broadcast[Foo](2))
  val merge = b.add(Merge[Foo](2))
  source ~> func1() ~> broadcast.in
  broadcast.out(0).filter(_.country == "US") ~> usSpecificFilter ~> merge.in(0)
  broadcast.out(1).filter(_.country != "US") ~> internationalFilter ~> merge.in(1)
  merge.out ~> s.in // <--- changed sink to s.in
  ClosedShape
})

java.lang.IllegalArgumentException：要求失败：inlets []和outlets []必须对应于inlet [Map.in]和outlet []

1 个答案: