Question

我正在使用citation（）来自动获取R包的bib条目。但是，它的输出没有密钥。

示例：

utils:::print.bibentry(citation(), style = "Bibtex")

输出：

@Manual{,
  title = {R: A Language and Environment for Statistical Computing},
  author = {{R Core Team}},
  organization = {R Foundation for Statistical Computing},
  address = {Vienna, Austria},
  year = {2017},
  url = {https://www.R-project.org/},
}

我想要这样的事情：

@Manual{mykey999,
  title = {R: A Language and Environment for Statistical Computing},
  author = {{R Core Team}},
  organization = {R Foundation for Statistical Computing},
  address = {Vienna, Austria},
  year = {2017},
  url = {https://www.R-project.org/},
}

我用＆＃34;键＆＃34;尝试了相同的命令。参数，但它什么都没改变：

utils:::print.bibentry(citation(), style = "Bibtex", key= "mykey0")

有什么想法吗？

Answer 1

你可以做到

z = citation()
z$key = "Hullo"
print(z, "Bibtex")

给出了

@Manual{Hullo,
  title = {R: A Language and Environment for Statistical Computing},
  author = {{R Core Team}},
  organization = {R Foundation for Statistical Computing},
  address = {Vienna, Austria},
  year = {2017},
  url = {https://www.R-project.org/},
}

或者，有一个愚蠢的单行：

print(`$<-`(citation(), key, "Hullo"), "Bibtex")

我想使用:::来访问print（如在OP中）在这里是过度的。但是，如果你喜欢看内幕，可能会对utils:::`$<-.bibentry`感到愤怒。从那里，你可以看到预期的任务是......

utils:::bibentry_attribute_names
# [1] "bibtype"     "textVersion" "header"      "footer"      "key"

Answer 2

无论何时R用户应用该函数，它们将通过函数本身的定义得到相同的结果。你必须复制输出结果（bib条目）或将其写入文件，然后你可以选择和你想要的任何bibkey的bibkey。

R在citation（）输出中丢失了bib键

2 个答案: