Question

我正在为我的网站制作一份清单部分。我有一个名为佣金的模型，其中包含有关调试任务的数据。我需要做的是当创建一个新的佣金条目时，我需要创建一系列约30个将链接到它的佣金任务。一种预定义值的清单，供人们浏览和检查。最好的方法是什么？

以下是我的模型和控制器：

commission.rb

    class Commission < ApplicationRecord
      has_many :comtasks
      belongs_to :project
      belongs_to :user
      accepts_nested_attributes_for :comtasks, allow_destroy: true
    end

comtask.rb

    class Comtask < ApplicationRecord
      belongs_to :commission
      belongs_to :user
    end

commissions_controller.rb

    class CommissionsController < ApplicationController
      before_action :set_commission, only: [:show, :edit, :update, :destroy]
      # GET /commissions
      # GET /commissions.json
      def index
        @commissions = Commission.all
      end

      # GET /commissions/1
      # GET /commissions/1.json
      def show
      end

      # GET /commissions/new
      def new
        @commission = Commission.new
      end

      # GET /commissions/1/edit
      def edit
      end

      # POST /commissions
      # POST /commissions.json
      def create
        @commission = Commission.new(commission_params)

        respond_to do |format|
          if @commission.save
            format.html { redirect_to @commission, notice: 'Commission was successfully created.' }
            format.json { render :show, status: :created, location: @commission }
          else
            format.html { render :new }
            format.json { render json: @commission.errors, status: :unprocessable_entity }
          end
        end
      end

      # PATCH/PUT /commissions/1
      # PATCH/PUT /commissions/1.json
      def update
        respond_to do |format|
          if @commission.update(commission_params)
            format.html { redirect_to @commission, notice: 'Commission was successfully updated.' }
            format.json { render :show, status: :ok, location: @commission }
          else
            format.html { render :edit }
            format.json { render json: @commission.errors, status: :unprocessable_entity }
          end
        end
      end

      # DELETE /commissions/1
      # DELETE /commissions/1.json
      def destroy
        @commission.destroy
        respond_to do |format|
          format.html { redirect_to commissions_url, notice: 'Commission was successfully destroyed.' }
          format.json { head :no_content }
        end
      end

      private
        # Use callbacks to share common setup or constraints between actions.
        def set_commission
          @commission = Commission.find(params[:id])
        end


        # Never trust parameters from the scary internet, only allow the white list through.
        def commission_params
          params.require(:commission).permit(:project_id, :user_id, :description, :objectname, :location, comtasks_attributes: [:id, :content, :notes])
        end
    end

感谢任何想法或建议。

Answer 1

以下是这个想法，

def create
  @commission = Commission.create!(commission_params)
  # use create not new to generate @commission.id value
  # so comtask records can use the id value as reference
  create_comtasks_job
  # for comtask create I put in other method
  respond_to do |format|
    if @commission.save

      format.html { redirect_to @commission, notice: 'Commission was successfully created.' }
      format.json { render :show, status: :created, location: @commission }
    else
      format.html { render :new }
      format.json { render json: @commission.errors, status: :unprocessable_entity }
    end
  end
end

def create_comtasks_job
  # loop 30 tasks / or manual as follow
  @commission.comtasks.build(content: 'content1',notes:'notes1')
  @commission.comtasks.build(content: 'content2',notes:'notes2')
end

您模型的其他代码

确保您的模型与下面的示例有关系

为您的模型

  class Commission < ActiveRecord::Base
    has_many :comtasks
  end

  class Comtask < ActiveRecord::Base
    belongs_to :commission
  end

Rails在创建

1 个答案:

您模型的其他代码