Question

为什么params_for没有通过变更集模型是主要问题。 params_for为postal_code生成4位数和2个字母（可以是小写或大写）。如果params_for将通过变更集，那么之后它将全部为大写。为什么这个测试目前失败了？

错误讯息：Expected truthy, got nil

我是一个公司模型，有这个变化集：

def changeset(company, params \\ %{}) do
  company
  ...
  |> maybe_sanitize_postal_code(:postal_code)
  ...
end

defp maybe_sanitize_postal_code(changeset, attr) do
  case get_change(changeset, attr) do
    nil -> changeset
    postal_code -> put_change(changeset, attr, sanitize_postal_code(postal_code))
  end
end

defp sanitize_postal_code(postal_code) do
  postal_code
  |> String.replace(~r/\s+/, "")
  |> String.upcase()
end

我有这个测试：

test "create company with postal code", %{conn: conn, user: user} do
  params = params_for(:company)
  conn = post conn, company_path(conn, :create), company: params
  assert json_response(conn, 201)["company"]["id"]
  company = Repo.get_by(Company, params)
  assert company
  assert [user] == Repo.all Ecto.assoc(company, :users)
  ...
end

params_for docs：https://hexdocs.pm/ex_machina/ExMachina.Ecto.html#c:params_for/2

Answer 1

如果params包含小写的postal_code，它会被变更集提升。但是，Repo.get_by(Company, params)仍会查找小写邮政编码，并返回nil

为什么params_for没有通过变更集？

1 个答案: