Question

我有两个数组。

 var a = ["a","b","c","d"];
 var b = ["c","d","f","k"];

这是我的两个数组。现在我需要检查两个数组中的任何单个匹配值。在找到单个匹配值后应该中断。

我期待的结果是c和d匹配。

Answer 1

您可以使用Array#find来迭代其中一个数组，Array#indexOf 或Array#includes查找该项是否存在于第二个数组中：

var a = ["a", "b", "c", "d"];
var b = ["c", "d", "f", "k"];

function findMatch(arr1, arr2) {
  return arr1.find(function(item) {
    return arr2.indexOf(item) === -1;
  });
}

var result = findMatch(a, b);

console.log(result);

带箭头功能和功能的花哨版本：

const a = ["a","b","c","d"];
const b = ["c","d","f","k"];

const findMatch = (arr1, arr2) => arr1.find((item) =>  arr2.includes(item));

const result = findMatch(a, b);

console.log(result);

Answer 2

如果你只是想知道是否有重复的内容，这将有效：

 a.some(x => b.some(y => y === x));

如果内容重复，会为您提供 true 。

如果你想要一个数组中的每个匹配内容

a.filter(x => b.some(y => x === y));

将为您提供['c', 'd']

Answer 3

你可以通过以下方式完成

＆＃13;

var a = ["a","b","c","d"];
 var b = ["c","d","f","k"];
 
 let ans = a.reduce(function(x, y){
    if(x == null){
        if(b.indexOf(y) > -1){
            return y;
        }
    }
    return x;
 }, null);
 
 console.log(ans);

＆＃13;

Answer 4

我遍历第一个数组并检查第二个数组中每个值的索引。

如果索引是＆gt; -1，然后将其推送到返回的数组。

＆＃13;

Array.prototype.diff = function(arr2) {
    var ret = [];
    for(var i in this) {   
        if(arr2.indexOf( this[i] ) > -1){
            ret.push( this[i] );
        }
    }
    return ret;
};

var array1 = ["cat", "sum","fun", "run", "hut"];
var array2 = ["bat", "cat","dog","sun", "hut", "gut"];

console.log( array1.diff(array2) );

＆＃13;

Answer 5

您可以使用filter()和every()来实现您的目标：

＆＃13;

var a = ["a","b","c","d"];
var b = ["c","dx","f","k"];
var isMatched = false;
    result = a.filter(x =>{
        b.every(s => { return isMatched = s!==x});
      });
   
console.log(!isMatched);

＆＃13;

如何在js中找到两个数组中的单个匹配值

5 个答案: