Question

我有一个表单，用于键入访客列表的联系人。在提交按钮被键入后，在同一页面上我想检索数据并显示访客列表。键入表单的数据在数据库中接收。但它们不会显示在HTML网站的屏幕上。

我邀请的顶部.HTML：

<?php 
include("guestlist.php");
include("guestlist_connect.php");
?>

invites.HTML：

<h2 >Invites & Guest List</h2> 
<table border="2">
  <thead>
    <tr>
      <th>First Name</th>
      <th>Last Name</th>
      <th>Contact</th>
      <th>Invitation</th>
    </tr>
  </thead>
  <tbody>
  <?php
    include("guestlist_connect.php");
    $result = mysql_query("SELECT * FROM guestlist");
    while( $row = mysql_fetch_assoc( $result ) ){
  ?>
      <tr>
        <td><? php echo $row["fname"]; ?></td>
        <td><? php echo $row["lname"]; ?></td>
        <td><? php echo $row["email"]; ?></td>
        <td><? php echo $row["contact"]; ?></td>
      </tr>
  <?php
  </tbody>
</table>
<?php  mysql_close($connector); ?>
</div><!--End Rightcontainer-->
</div>

_guestlist_connect.php：_

<?php
$servername = "localhost";
$username = "root";
$password = "";
$dbname = "registration";
$conn = mysqli_connect($servername, $username, $password, $dbname) or 
die("Connection failed: " . mysqli_connect_error());
if (mysqli_connect_errno()) {
  printf("Connect failed: %s\n", mysqli_connect_error());
  exit();
}
?>

Answer 1

首先，您不需要重复包括（＆＃34; guestlist_connect.php＆＃34）; 而且你忘了在循环结束时结束

CREATE TABLE DEMO (COLA VARCHAR(10) NOT NULL, COLB VARCHAR(10) NOT NULL, COLC VARCHAR(10), COLD VARCHAR(10));

ALTER TABLE DEMO ADD CONSTRAINT DEMO_PK PRIMARY KEY (COLA, COLB);

CREATE INDEX DEMO_IX1 ON DEMO (COLB);



INSERT INTO DEMO VALUES ('A','B','C','D');
INSERT INTO DEMO VALUES ('A1','B1','C1','D1');
INSERT INTO DEMO VALUES ('A2','B2','C2','D2');

SELECT COLA,COLB FROM DEMO WHERE COLB='B1'

来自数据库的数据未出现在HTML网站的表格中

1 个答案: