我有这样的数据结构:
var fieldTmp= [{
"CountryDetails":[{
"countryName":"Kerala",
"JobDetails":[{
"RequisitionId":"00020447961",
"City":"KOCHI",
"PostedDate":"2016-12-18"
},{
"RequisitionId":"26103",
"City":"TRIVANDRUM",
"PostedDate":"2016-12-12"
},{
"RequisitionId":"26077",
"City":"ALAPPEY",
"PostedDate":"2016-10-09"
},{
"RequisitionId":"00020774701",
"City":"KOTTAYAM",
"PostedDate":"2016-06-12"
},{
"RequisitionId":"26078",
"City":"ADOOR",
"PostedDate":"2016-05-19"}]
},
"countryName":"MADRAS",
"JobDetails":[{
"RequisitionId":"0025456",
"City":"CHENNAI",
"PostedDate":"2017-06-05"
},{
"RequisitionId":"69847562",
"City":"ADYAR",
"PostedDate":"2016-10-14"}]
},
{"countryName":"Tamil Nadu",
"JobDetails":[{
"RequisitionId":"00020550501",
"City":"CHENNAI",
"PostedDate":"2016-12-18"
},{
"RequisitionId":"00020786022",
"City":"KOVAI",
"PostedDate":"2016-09-01"
},{
"RequisitionId":"00020786071",
"City":"TRICHY",
"PostedDate":"2016-04-10"}]
}] }]
我的要求是,我需要在MADRAS下向Tamil Nadu添加作业详细信息,我需要根据一个属性-PostedDate对数据进行排序。 所以我的结果应该是这样的,
var fieldTmp= [{
"CountryDetails":[{
"countryName":"Kerala",
"JobDetails":[{
"RequisitionId":"00020447961",
"City":"KOCHI",
"PostedDate":"2016-12-18"
},{
"RequisitionId":"26103",
"City":"TRIVANDRUM",
"PostedDate":"2016-12-12"
},{
"RequisitionId":"26077",
"City":"ALAPPEY",
"PostedDate":"2016-10-09"
},{
"RequisitionId":"00020774701",
"City":"KOTTAYAM",
"PostedDate":"2016-06-12"
},{
"RequisitionId":"26078",
"City":"ADOOR",
"PostedDate":"2016-05-19"}]
},
{"countryName":"Tamil Nadu",
"JobDetails":[{
"RequisitionId":"0025456",
"City":"CHENNAI",
"PostedDate":"2017-06-05"
},{
"RequisitionId":"00020550501",
"City":"CHENNAI",
"PostedDate":"2016-12-18"
},{
"RequisitionId":"69847562",
"City":"ADYAR",
"PostedDate":"2016-10-14"
},{
"RequisitionId":"00020786022",
"City":"KOVAI",
"PostedDate":"2016-09-01"
},{
"RequisitionId":"00020786071",
"City":"TRICHY",
"PostedDate":"2016-04-10"}]
}] }]
我试图提取Madras数据并将其添加到Tamil Nadu下。但没有任何工作。 我知道如何从JSON对象中提取单个或多个值。但我需要编辑JSON并对其进行排序。我能够做到。
答案 0 :(得分:0)
我得到了解决方案。 当 countryName 是“Tamil Nadu”和“MADRAS”时,我提取了所有数据并使用下面的代码将其保存在新数组中。
function mergingBothStateDetails(jsonJobDetails){
for(var j=0;j<jsonJobDetails.length;j++)
{
newTmpRecord.push({"RequisitionId":jsonJobDetails[j].RequisitionId,
"PostedDate":jsonJobDetails[j].PostedDate,
"City":jsonJobDetails[j].City});
}
}
这里 newTmpRecord 是一个数组,就像通用变量
对于排序我使用下面的代码
function sortNewList(){
newTmpRecord.sort(function(a, b){ // sort object by retirement date
var dateA=new Date(a.PostedDate), dateB=new Date(b.PostedDate)
return dateB-dateA //sort by date descending
});
}
答案 1 :(得分:-2)
您可以简单地提取对象&#34; Madras&#34;从数组中将所有Jobdetails添加到对象&#34; Tamil Nadu&#34;在for循环中。您可以通过检查日期来查看在循环中添加它们的位置,或者您可以编写一个排序函数,这在javascript中非常简单,并在此处进行了详细解释: