Question

我正在开发一个Jax Ws，我想添加Soap Handler用于WS身份验证。添加了一个处理程序链xml和一个Soap Handler类，但代码从不调用Soap Handler的方法。我使用JDK 8和Tomcat 7.可能是什么问题？我的处理程序链xml如下：

>9

我的肥皂处理程序类a：

    <?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<!DOCTYPE javaee:handler-chains>
<javaee:handler-chains xmlns:javaee="http://java.sun.com/xml/ns/javaee"
    xmlns:xsd="http://www.w3.org/2001/XMLSchema">
    <javaee:handler-chain>
        <javaee:handler>
            <javaee:handler-class>com.vw.AuthHandler
            </javaee:handler-class>
        </javaee:handler>
    </javaee:handler-chain>
</javaee:handler-chains>

我的服务如下：

import java.io.PrintStream;
import java.io.StringReader;
import java.util.Collections;
import java.util.Set;

import javax.xml.bind.JAXBContext;
import javax.xml.bind.JAXBException;
import javax.xml.namespace.QName;
import javax.xml.soap.SOAPException;
import javax.xml.soap.SOAPHeader;
import javax.xml.ws.handler.MessageContext;
import javax.xml.ws.handler.soap.SOAPHandler;
import javax.xml.ws.handler.soap.SOAPMessageContext;
import org.w3c.dom.Element;
import org.w3c.dom.Node;

public class AuthHandler implements SOAPHandler<SOAPMessageContext> {

       private static PrintStream out = System.out;  
       @Override
       public Set<QName> getHeaders() {
          return Collections.emptySet();
       }

    @Override
    public boolean handleMessage(SOAPMessageContext context) {  
         Boolean outboundProperty = (Boolean) context.get(MessageContext.MESSAGE_OUTBOUND_PROPERTY);         
              if (!outboundProperty) {              
                        System.out.println("Hello!");
                    return true;   
              }
              return false;
    }
        @Override
    public boolean handleFault(SOAPMessageContext context) {
        System.out.println("Hello!");
        return false;
    }

    @Override
    public void close(MessageContext context) {
        System.out.println("Hello!");

    }

}

永远不会调用WS Soap Handler类

0 个答案: