Question

此错误随机出现在我们的MVC应用中。有时做同样的事情，有时也不会。有没有人知道这是否与任何可能是简单修复的事情有关，或者这是很多人见过的常见事情？

System.InvalidOperationException: This request has been blocked because sensitive information could be disclosed to third party web sites when this is used in a GET request. To allow GET requests, set JsonRequestBehavior to AllowGet.
   at System.Web.Mvc.JsonResult.ExecuteResult(ControllerContext context)
   at System.Web.Mvc.ControllerActionInvoker.InvokeActionResult(ControllerContext controllerContext, ActionResult actionResult)
   at System.Web.Mvc.ControllerActionInvoker.<>c__DisplayClass14.b__11()
   at System.Web.Mvc.ControllerActionInvoker.InvokeActionResultFilter(IResultFilter filter, ResultExecutingContext preContext, Func`1 continuation)
   at System.Web.Mvc.ControllerActionInvoker.<>c__DisplayClass14.<>c__DisplayClass16.b__13()
   at System.Web.Mvc.ControllerActionInvoker.InvokeActionResultFilter(IResultFilter filter, ResultExecutingContext preContext, Func`1 continuation)
   at System.Web.Mvc.ControllerActionInvoker.<>c__DisplayClass14.<>c__DisplayClass16.b__13()
   at System.Web.Mvc.ControllerActionInvoker.InvokeActionResultFilter(IResultFilter filter, ResultExecutingContext preContext, Func`1 continuation)
   at System.Web.Mvc.ControllerActionInvoker.<>c__DisplayClass14.<>c__DisplayClass16.b__13()
   at System.Web.Mvc.ControllerActionInvoker.InvokeActionResultWithFilters(ControllerContext controllerContext, IList`1 filters, ActionResult actionResult)
   at System.Web.Mvc.ControllerActionInvoker.InvokeAction(ControllerContext controllerContext, String actionName)
   at System.Web.Mvc.Controller.ExecuteCore()
   at System.Web.Mvc.ControllerBase.Execute(RequestContext requestContext)
   at System.Web.Mvc.ControllerBase.System.Web.Mvc.IController.Execute(RequestContext requestContext)
   at System.Web.Mvc.MvcHandler.<>c__DisplayClass8.b__4()
   at System.Web.Mvc.Async.AsyncResultWrapper.<>c__DisplayClass1.b__0()
   at System.Web.Mvc.Async.AsyncResultWrapper.<>c__DisplayClass8`1.b__7(IAsyncResult _)
   at System.Web.Mvc.Async.AsyncResultWrapper.WrappedAsyncResult`1.End()
   at System.Web.Mvc.MvcHandler.EndProcessRequest(IAsyncResult asyncResult)
   at System.Web.Mvc.MvcHandler.System.Web.IHttpAsyncHandler.EndProcessRequest(IAsyncResult result)
   at System.Web.HttpApplication.CallHandlerExecutionStep.System.Web.HttpApplication.IExecutionStep.Execute()
   at System.Web.HttpApplication.ExecuteStep(IExecutionStep step, Boolean& completedSynchronously)

Answer 1

您的问题的答案在堆栈跟踪中。 “JsonRequestBehavior to AllowGet”

所以在你的Controller中使用它：

return Json(data, JsonRequestBehavior.AllowGet)

Answer 2

在绕过这些安全控制之前，您应该阅读http://haacked.com/archive/2009/06/24/json-hijacking.aspx/。

如果您只是公开您的JSON数据以响应Http POST，那么您就不会受到此攻击。

您可以使用[HttpPost]简单地注释您的JSON操作，并在客户端执行类似

的操作

$.post('/blag/JSON', function (data) {
       //do something with my json data object here

});

Answer 3

您似乎有时会根据HTTP GET调用控制器操作。为了能够返回JSON结果，您应该使用像

这样的代码

return Json(data, JsonRequestBehavior.AllowGet);

Answer 4

＆＃13;

return Json(PartialView("index").ToJsonObject(this), JsonRequestBehavior.AllowGet);

＆＃13;

Json允许错误

4 个答案: