Question

import math
def maths():
  shape=input("Choose a shape:Square, Circle or Triangle ")
  if shape == "Triangle" or "triangle":
    triangleb = int(input("How many cm's is the base of your triangle? "))
    triangleh = int(input("How many cm's is the height of your triangle? "))
    t_area = triangleb*triangleh / 2
    print("The area of your triangle is",t_area)
    print("")
    maths()

  elif shape == "Circle" or "circle":
    circle=int(input("What is the radius of your circle? "))
    c_area=math.pi*circle*circle
    c_arearound=round(c_area ,2)
    print("The area of your circle is",c_arearound,"(rounded to 2 decimal places)")
    print("")
    maths()

 elif shape == "square" or "Square":
    square=int(input("How many cm is one side of your square "))
    s_area=square*square
    print("The area of your square is",s_area)
    print("")
    maths()
 else:
    print("invalid answer")
    maths()

maths()

IF语句的每个元素在以＆＃39; if开头时都能正常工作。问题是，如果我输入＆＃39; circle＆＃39;将出现三角形的代码。例如，我会输入圆圈，它会说“你的三角形的底部有多少厘米？”＆＃39;。无论我输入什么，无论是圆形还是方形，它都会打印出三角形代码。如果我切换＆＃39; if＆＃39;圆形而不是三角形的语句完全相同。我可以输入三角形或正方形，无论输入是什么，它都只会运行圆形代码。为什么？

Python-My IF语句不起作用

0 个答案: