我的数据库是这样的:
user123 是管理员。因此,他应该能够遍历条目中的所有节点。其他人看不到条目的孩子,除非entryID的 uid 是 auth.uid
我该如何为此制定规则?如果没有可能的方法,任何改变dataBase的建议:)
答案 0 :(得分:2)
如果你已经知道admin是,那么在你的问题user123。那你的数据库规则应该是
"entities": {
"$entryId":{
// you don't what others to see other to see teh data
".read": "auth.uid == 'user123'"
// any one who is logged in should write to the /entries node
".write": "auth.uid != null"
}
}
如果您要使规则更具动态性,那么您可以
"entities": {
"$entityId":{
// you don't what others to see other to see teh data
".read": "root.child('users').child(auth.uid).child('isAdmin').val() == true || root.child('entities').child($entityId).child('uid').val() == auth.uid"
// any one who is logged in should write to the /entries node
".write": "auth.uid != null"
}
}
您可以从https://firebase.google.com/docs/reference/security/database/
获取更多信息或者,您可以将条目模型更改为用户特定的
{
"entities" :{
"user465": {
"entry456": {
"text" : "Some sample text"
}
}
}
}
在这种情况下,你写了规则
"entities": {
"$userId":{
// you don't what others to see other to see teh data
".read": "root.child('users').child(auth.uid).child('isAdmin').val() == true || $userId == auth.uid"
// any one who is logged in should write to the /entries node
".write": "auth.uid == $userId"
}
}