Question

我有这个型号：

class Post(models.Model):
    id = models.UUIDField(primary_key=True, default=uuid.uuid4, editable=False)
    title = models.CharField()
    user = models.ForeignKey('users.User')

这个ModelAdmin：

class PostAdmin(admin.ModelAdmin):
    list_display = ['title', 'user']
    list_filter = ['user']

过滤效果很好，但我遇到了这样的问题。在我的情况下users.User表非常大，所以当Django呈现PostAdmin页面时，渲染所有用户需要太多时间。

所以我想知道是否可以将Django Admin过滤器与ForeignKey一起使用而不渲染所有相关对象，例如raw_id_fields小部件用于过滤器？

Answer 1

我能够找到的最佳解决方案是使用raw_id_field小部件自定义Filter。

创建模板user_filter.html：

{% load static %}
<link rel="stylesheet" type="text/css" href="{% static 'admin/css/forms.css' %}"/>
<script type="text/javascript">var go_from_select = function(opt) { window.location = window.location.pathname + opt };</script>
<h3>{{ title }}</h3>
<div class="admin-filter-user" style="margin-left:15px">
    <input type="text" style="display:inline-block;" name="{{title}}" value="{{ request.GET.user__id__exact }}" id="id_{{title}}" class="vForeignKeyRawIdAdminField"/>
    <a href="{% url 'admin:users_user_changelist' %}" class="related-lookup" style="display:inline-block;" id="lookup_id_{{title}}" title="Lookup"></a>
    <input type="button" onclick="go_from_select('?user__id__exact='+id_user.value)" value="Filter" />
    <a href="#" style="display:inline-block; margin-left:7px" onclick="go_from_select('')">clear</a>
</div>

创建新的Filter类并覆盖默认模板：

class UserFilter(admin.RelatedFieldListFilter):
    """Raw_id_filter for user field"""
    template = 'admin/user_filter.html'

将UserFilter设置为ModelAdmin中用户字段的过滤器类：

class PostAdmin(admin.ModelAdmin):
    list_display = ['title', 'user']
    list_filter = [('user', UserFilter)]

这将为user过滤器设置raw_id_field小部件并提高页面呈现性能。

Answer 2

我刚刚发现https://github.com/lincolnloop/django-salmonella看起来会为任何FK提供原始ID过滤器。

# pip install django-salmonella

from salmonella.admin import SalmonellaMixin
from salmonella.filters import SalmonellaFilter

class UserProfileAdmin(SalmonellaMixin, admin.ModelAdmin):
   list_filter = (
       ('salmonella_fk', SalmonellaFilter),
   )

您还可以清除grapelli https://www.abidibo.net/blog/2015/02/06/pretty-raw_id_fields-django-salmonella-and-django-grappelli/

的样式 app/templates/salmonella/admin/widgets/salmonella_field.html

中的

{{ hidden_input }}
<a onclick="return showRelatedObjectLookupPopup(this);" id="lookup_id_{{ name }}" data-name="{{ name }}" data-app="{{ app_name }}" data-model="{{ model_name }}" class="related-lookup" href="{{ related_url }}{{ url }}"><img width="16" height="16" alt="Consultazione" src="/static/admin/img/selector-search.gif"></a>
<a data-name="developers" data-app="{{ app_name }}" data-model="{{ model_name }}" class="salmonella-clear-field"></a>
<span class="salmonella_label" id="{{ name }}_salmonella_label"></span>

和app/templates/salmonella/multi_label.html

{% for object in objects %}
    <a href="{{ object.1 }}" >{{ object.0 }}</a>{% if not forloop.last %} {% endif %}
{% endfor %}

和样式表：

.salmonella-clear-field {
    background-image: url("/static/grappelli/images/icons/related-remove.png");
    background-repeat: no-repeat;
    background-position: center center;
    display: inline-block;
    position: relative;
    top: 5px;
    margin: 0 5px 0 10px;
    height: 15px;
    width: 15px;
    cursor: pointer;
}
.salmonella_label {
    position: inline-block;
    position: relative;
    top: 2px;
}
.salmonella_label a {
    background: #fff;
    padding: 2px 5px;
}

Django admin list_filter具有大型相关表

2 个答案: