我正在编写一个简单的函数来创建一个代表一副牌的列表。 这是结构的定义
typedef struct {
float valoreEff;
char *seme;
char *valore;
} carta;
struct Mazzo {
carta info;
struct Mazzo *nextPtr;
};
typedef struct Mazzo mazzo;
typedef mazzo *mazzoPtr;
这是返回指向列表第一个元素
的指针的函数mazzoPtr caricaMazzo(void){
mazzoPtr sMazzoPtr=NULL;
int val,seme;
carta buffer;
mazzoPtr newPtr;
char *tabValori[10]={"Asso","Due","Tre","Quattro","Cinque","Sei","Sette","Donna","Cavallo","Re"};
char *tabSeme[4]={"Denari","Spade","Coppe","Bastoni"};
for(seme=0;seme<4;seme++){
for(val=0;val<10;val++){
buffer.seme=tabSeme[seme];
buffer.valore=tabValori[val];
if (val<=7) {
buffer.valoreEff=val+1;
}
else {
buffer.valoreEff=0.5;
}
printf("ok\n");
newPtr=malloc(sizeof(carta));
if (newPtr==NULL){
printf("Memoria insufficiente\n");
return NULL;
}
newPtr->info=buffer;
newPtr->nextPtr=sMazzoPtr;
sMazzoPtr=newPtr;
}
}
return sMazzoPtr;
}
GCC没有给我编译时错误,但是当我执行程序时,这就是输出
ok
ok
main: malloc.c:3096: sYSMALLOc: Assertion `(old_top == (((mbinptr) (((char *)
&((av)->bins[((1) - 1) * 2])) - __builtin_offsetof (struct malloc_chunk, fd))))
&& old_size == 0) || ((unsigned long) (old_size) >= (unsigned long)
((((__builtin_offsetof (struct malloc_chunk, fd_nextsize))+((2 *
(sizeof(size_t))) - 1)) & ~((2 * (sizeof(size_t))) - 1))) && ((old_top)->size
& 0x1) && ((unsigned long)old_end & pagemask) == 0)' failed.
Aborted
我也试过Valgrind,但我无法弄清楚代码中的错误。
==21848== Invalid write of size 4
==21848== at 0x8048554: caricaMazzo (in /home/gianluca/Dropbox/PROGRAMMI/progetto/main)
==21848== by 0x8048431: main (in /home/gianluca/Dropbox/PROGRAMMI/progetto/main)
==21848== Address 0x419e034 is 0 bytes after a block of size 12 alloc'd
==21848== at 0x4025BD3: malloc (vg_replace_malloc.c:236)
==21848== by 0x804851D: caricaMazzo (in /home/gianluca/Dropbox/PROGRAMMI/progetto/main)
==21848== by 0x8048431: main (in /home/gianluca/Dropbox/PROGRAMMI/progetto/main)
==21848==
我希望你能帮助我:)。
答案 0 :(得分:5)
问题似乎出现在您致电malloc()
的行。
newPtr
的类型为mazzo*
,但您要为carta
分配空间,这个空间太小了。
我认为它应该是newPtr=malloc(sizeof(mazzo));
答案 1 :(得分:0)
虽然这可能不适合您,但最好还是使用C ++。在其众多软件工程优势中,其new
用于分配内存的习惯用法可以防止出现这种错误,因为您必须明确使用对象类型:newPtr = new mazzo;