如何从DateTime中减去多个工作日(不是周六或周日)?
方法签名应为:
void SubtractBusinessDays(ref DateTime dt,int BusinessDaysToSubtract)
由于
答案 0 :(得分:2)
这是您可以使用的扩展方法。随意将其重构为一种简单的方法。
/// <summary>
/// Adds weekdays to date
/// </summary>
/// <param name="value">DateTime to add to</param>
/// <param name="weekdays">Number of weekdays to add</param>
/// <returns>DateTime</returns>
public static DateTime AddWeekdays(this DateTime value, int weekdays)
{
int direction = Math.Sign(weekdays);
int initialDayOfWeek = Convert.ToInt32(value.DayOfWeek);
//---------------------------------------------------------------------------
// if the day is a weekend, shift to the next weekday before calculating
if ((value.DayOfWeek == DayOfWeek.Sunday && direction < 0)
|| (value.DayOfWeek == DayOfWeek.Saturday && direction > 0))
{
value = value.AddDays(direction * 2);
weekdays += (direction * -1); // adjust days to add by one
}
else if ((value.DayOfWeek == DayOfWeek.Sunday && direction > 0)
|| (value.DayOfWeek == DayOfWeek.Saturday && direction < 0))
{
value = value.AddDays(direction);
weekdays += (direction * -1); // adjust days to add by one
}
//---------------------------------------------------------------------------
int weeksBase = Math.Abs(weekdays / 5);
int addDays = Math.Abs(weekdays % 5);
int totalDays = (weeksBase * 7) + addDays;
DateTime result = value.AddDays(totalDays * direction);
//---------------------------------------------------------------------------
// if the result is a weekend, shift to the next weekday
if ((result.DayOfWeek == DayOfWeek.Sunday && direction > 0)
|| (result.DayOfWeek == DayOfWeek.Saturday && direction < 0))
{
result = result.AddDays(direction);
}
else if ((result.DayOfWeek == DayOfWeek.Sunday && direction < 0)
|| (result.DayOfWeek == DayOfWeek.Saturday && direction > 0))
{
result = result.AddDays(direction * 2);
}
//---------------------------------------------------------------------------
return result;
}
答案 1 :(得分:0)
你能不能只获得天数,然后是mod 7,并从原始天数中减去该值* 2,如果当天是星期六或星期日,则减去1或2?