Question

我在为此创建查询时遇到困难。以下是表格。

CREATE TABLE [dbo].[Mst_Conflict_Roles]
(
    [CRLm_ID] [dbo].[ITS_BID] IDENTITY(1,1) NOT NULL,
    [CRLm_Roles] [varchar](10) NOT NULL,
    [CRLm_Description] [varchar](200) NULL,
    [CRLm_Added_By] [dbo].[ITS_UserID] NOT NULL,
    [CRLm_Added_Dt] [dbo].[ITS_Datetime] NOT NULL,
    [CRLm_Last_Updated_By] [dbo].[ITS_UserID] NULL,
    [CRLm_Last_Updated_Dt] [dbo].[ITS_Datetime] NULL,
    [CRLm_data_del] [dbo].[ITS_TID] NOT NULL,

    CONSTRAINT [PK_Mst_Conflict_Roles] 
        PRIMARY KEY CLUSTERED ([CRLm_ID] ASC)
) ON [PRIMARY]

INSERT INTO [Mst_Conflict_Roles]
VALUES ('2,113', 'Scheduler - Auditor', 1, GETDATE(), 1, GETDATE(), 0),
       ('110,113','AE - Scheduler',1,GETDATE(),1,GETDATE(),0),
       ('2,121','Auditor - Vendor CAP User',1,GETDATE(),1,GETDATE(),0),
       ('8,9','AM - AC',1,GETDATE(),1,GETDATE(),0)



declare @userRole as table(userID int, userRole int)
Insert into @userRole values (1, 2),(1, 113),(1, 8),(1, 9),(1, 50),(2, 110),(2, 50),(3, 2),(3, 121)

select * from @userRole

逻辑：如果用户角色（userRole）与冲突表角色（CRLm_Roles）匹配，则记录必须出现在输出表中。

输出

UserID  CRLm_ID CRLm_description
1          1       2,113
1          4       8,9
3          3       2,121

有谁能告诉我如何处理这个问题？

Answer 1

以下查询返回所需的输出：

WITH    tmp ( CRLm_ID, CRLm_Roles, Role_ID, Data )
      AS ( SELECT   CRLm_ID ,
                    CRLm_Roles ,
                    CONVERT(NVARCHAR, LEFT(CRLm_Roles,
                                           CHARINDEX(',', CRLm_Roles + ',')
                                           - 1)) ,
                    STUFF(CRLm_Roles, 1, CHARINDEX(',', CRLm_Roles + ','),
                          '')
           FROM     [dbo].[Mst_Conflict_Roles]
           UNION ALL
           SELECT   CRLm_ID ,
                    CRLm_Roles ,
                    CONVERT(NVARCHAR, LEFT(Data,
                                           CHARINDEX(',', Data + ',') - 1)) ,
                    STUFF(Data, 1, CHARINDEX(',', Data + ','), '')
           FROM     tmp
           WHERE    Data > ''
         )
SELECT  UserID, CRLm_ID, CRLm_Roles AS CRLm_description
FROM    ( SELECT    CRLm_ID ,
                    CRLm_Roles ,
                    Role_ID ,
                    userRole.* ,
                    R = ROW_NUMBER() OVER ( PARTITION BY userID, CRLm_ID ORDER BY userID )
          FROM      tmp
                    JOIN userRole ON tmp.Role_ID = userRole.userRole
        ) x
WHERE   R = 2
OPTION (maxrecursion 0);

输出：

使用连接检查多行

1 个答案: