Question

所以，我有一个包含这样的字符串数组的字典：

vld1.32 {d0-d1}, [r0]

现在我必须能够从数组中删除一个值。例：我想删除“dev4”，无论它是在“Section1”还是“Section2”中。

我将如何做到这一点？

Answer 1

使用 Swift4 ，可以选择将地图应用于字典的值：

var dict = ["Section1": ["dev1", "dev2"], "Section2": ["dev3", "dev4"]]
dict = dict.mapValues{ $0.filter{ $0 != "dev4" } }

给出了结果：

dict // -> ["Section1": ["dev1", "dev2"], "Section2": ["dev3"]]

Answer 2

for key in dict.keys {
    dict[key] = dict[key]!.filter({ $0 != "dev4"})
}

Answer 3

一些示例代码：

func removeValue(value: String, fromDict dict: [String: [String]]) -> [String: [String]] {
    var out = [String: [String]]()
    for entry in dict {
        out[entry.key] = entry.value.filter({
            $0 != value
        })
    }
    return out
}

var dict = ["Section1": ["dev1", "dev2"], "Section2": ["dev3", "dev4"]]
let new = removeValue(value: "dev4", fromDict: dict)

Answer 4

迷你版：

dict.forEach({ (k, v) in dict[k] = v.filter({ $0 != "dev4" }) })
print(dict) // ["Section1": ["dev1", "dev2"], "Section2": ["dev3"]]

Swift Dictionary with String of Strings删除Value

4 个答案: