Question

以下是链接处理程序的代码：

link_patterns = {'http[s]?://www.facebook.[a-z]{2,3}/[A-Za-z0-9\.]*/videos/([0-9]+)*/':Facebook.get_video()}
def find_pattern(url):
    for pattern in link_patterns:
        if re.match(pattern, url):
            return link_patterns[pattern]
    return None

如何使用Facebook.get_video() dict键的正则表达式获取带有id参数的link_patterns？

Answer 1

Python 3版本：

link_patterns = {'http[s]?://www.facebook.[a-z]{2,3}/[A-Za-z0-9\.]*/videos/(vb.[0-9]+/){0,1}([0-9]+)*/':Facebook.get_video}
    def find_pattern(url):
        for pattern, action in link_patterns.items():
            matches = re.match(pattern, url)
            if matches:
                return matches.group(1), action
                # or capture group that contains id in your case
        return None

id, action = find_pattern(url)
if id:
    action(id)

您可以返回一个函数对象，然后使用id作为参数调用它

如何引用dict键

1 个答案: