Question

说我有以下html

$html = '
<div class="website">
    <div>
        <div id="old_div">
            <p>some text</p>
            <p>some text</p>
            <p>some text</p>
            <p>some text</p>
            <div class="a class">
                <p>some text</p>
                <p>some text</p>
            </div>
        </div>
        <div id="another_div"></div>
    </div>
</div>
';

我想用以下内容替换#old_div：

$replacement = '<div id="new_div">this is new</div>';

给出最终结果：

$html = '
<div class="website">
        <div>
            <div id="new_div">this is new</div>
            <div id="another_div"></div>
        </div>
    </div>
';

使用PHP执行此操作是否有简单的剪切和粘贴功能？

感谢所有戈登的帮助，最后的工作代码：

<?php

$html = <<< HTML
<div class="website">
    <div>
        <div id="old_div">
            <p>some text</p>
            <p>some text</p>
            <p>some text</p>
            <p>some text</p>
            <div class="a class">
                <p>some text</p>
                <p>some text</p>
            </div>
        </div>
        <div id="another_div"></div>
    </div>
</div>
HTML;

$dom = new DOMDocument;
$dom->loadXml($html); // use loadHTML if it's invalid XHTML

//create replacement
$replacement  = $dom->createDocumentFragment();
$replacement  ->appendXML('<div id="new_div">this is new</div>');

//make replacement
$xp = new DOMXPath($dom);
$oldNode = $xp->query('//div[@id="old_div"]')->item(0);
$oldNode->parentNode->replaceChild($replacement  , $oldNode);
//save html output
$new_html = $dom->saveXml($dom->documentElement);

echo $new_html;

?>

Answer 1

由于链接副本中的答案并不全面，我将举例说明：

$dom = new DOMDocument;
$dom->loadXml($html); // use loadHTML if its invalid (X)HTML

// create the new element
$newNode = $dom->createElement('div', 'this is new');
$newNode->setAttribute('id', 'new_div');

// fetch and replace the old element
$oldNode = $dom->getElementById('old_div');
$oldNode->parentNode->replaceChild($newNode, $oldNode);

// print xml
echo $dom->saveXml($dom->documentElement);

从技术上讲，你不需要XPath。但是，对于未经验证的文档（id attributes are special in XML），您的libxml版本可能无法getElementById。在这种情况下，请将呼叫替换为getElementById和

$xp = new DOMXPath($dom);
$oldNode = $xp->query('//div[@id="old_div"]')->item(0);

Demo on codepad

要创建一个带有子节点的$newNode而无需逐个创建和追加元素，您可以

$newNode = $dom->createDocumentFragment();
$newNode->appendXML('
<div id="new_div">
    <p>some other text</p>
    <p>some other text</p>
    <p>some other text</p>
    <p>some other text</p>
</div>
');

Answer 2

首先使用jquery hide（）隐藏特定div，然后使用append追加新div

$('#div-id').remove();
$('$div-id').append(' <div id="new_div">this is new</div>');

如何使用XPath和DOM替换php中的节点/元素？

2 个答案: