我不明白为什么代码不起作用,他们已经向我重复了4次问题。并说浮动不可调用。我已经尝试这样做了很长一段时间,但我似乎什么也得不到。是否有更容易的方式python3?我刚刚在两周前学会了这门语言。对我而言,这不是一个全新的世界,而是我不熟悉的许多事物。例如缩进
def get_taxi_info():
flag_down = float(input("What's the flag-down fare: $"))
within = float(input("What's the rate per 400 meters within 9.8km? $"))
beyond = float(input("What's the rate per 350 meters beyond 9.8km? $"))
distance = float(input("What's the distance traveled (in meters)? "))
peak = input("Is the ride during a peak period? [yes/no]")
mid6 = input("Is the ride between midnight and 6am? [yes/no]")
location = input("Is there any location surcharge? [yes/no]")
surloca = float(input("What's the amount of location surcharge?"))
return (flag_down, within, beyond, distance, peak == 'yes', mid6 == 'yes', location == 'yes', surloca)
def calculate_taxi_fare():
dist = get_taxi_info()
if dist[3] > 9800:
extra = (dist[3] - 9800) % 350
if extra == 0:
a = (extra//350) + 22
else:
a = (extra//350) + 23
return a
elif dist[3] <= 9800:
extra = (dist[3] - 1000) % 400
if extra == 0:
a = (extra//400)
else:
a = (extra//400) + 1
return a
def peakornot():
peak = get_taxi_info()
if peak[4] == True and peak[5] == False:
surcharge = 1.25
return surcharge
elif peak[4] == False and peak[5] == True:
surcharge = 1.50
return surcharge
taxifare = calculate_taxi_fare()
info = get_taxi_info()
peak1 = peakornot()
taxifare = calculate_taxi_fare()
if info[6] == True:
payable = ((info[0] + (info[1] * taxifare()) + (info[2] * taxifare())) * peak1[0]) + info[7]
print ("The total fare is $" + str(payable))
elif info[6] == False:
payable = ((info[0] + (info[1] * taxifare()) + (info[2] * taxifare())) * peak1[0]) + info[7]
print ("The total fare is $" + str(payable))
答案 0 :(得分:2)
函数calculate_taxi_fare
返回float
,因此此行taxifare
为float
taxifare = calculate_taxi_fare()
因此你不能说taxifare()
因为它看起来像是一个函数调用,所以你可以使用例如
info[1] * taxifare