我试图用Newtonsoft的JSON库将JSON反序列化为C＃对象，但是我无法为它创建正确的类。我不知道为什么但我不能用json2sharp等生成类。 那就是我的JSON数据：
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这就是我现在所拥有的： https://ybin.me/p/a825152ddcde634a#JRwWC5wW2BA2bkiWEBllEy4+sJ0VPPs9KSzU21bJqUs= 我添加外部链接是因为这里的消息限制。 我得到的错误是：
类型＆＃39; Newtonsoft.Json.JsonSerializationException的未处理异常＆＃39;发生在Newtonsoft.Json.dll
无法将当前JSON数组（例如[1,2,3]）反序列化为类型＆＃39; MasterData＆＃39;因为该类型需要一个JSON对象（例如{＆＃34; name＆＃34;：＆＃34; value＆＃34;}）才能正确反序列化。
要修复此错误，请将JSON更改为JSON对象（例如{＆＃34; name＆＃34;：＆＃34; value＆＃34;}）或将反序列化类型更改为数组或实现的类型像List这样的集合接口（例如ICollection，IList）可以从JSON数组反序列化。 JsonArrayAttribute也可以添加到类型中，以强制它从JSON数组反序列化。
路径＆＃39;＆＃39;，第1行，第1位。
编辑：感谢您的回答。在该初始数据之后，Feed使用不同的格式。
[132,36988065,[["o",1,"2.84200012","0.00000000"],["o",1,"2.84200014","0.29990442"]]]
这是我尝试创建的类，但是我得到了如上所述的异常错误。
public class Small
{
public int Id { get; set; }
public long Seq { get; set; }
public InnerObjectSmall Obj { get; set; }
}
public class InnerObjectSmall
{
public string Id { get; set; }
public int OrderType { get; set; }
public List<Dictionary<decimal, decimal>> orderBook { get; set; }
}
答案 0 :(得分：1)
您必须创建一些自定义JsonConverter来实现此目的。基于数据，并且不了解数据背后的逻辑，这就是我想出的：
class Program
{
static void Main(string[] args)
{
var value = JsonConvert.DeserializeObject<MasterData>(beginingDataRaw);
}
}
[JsonConverter(typeof(MasterDataConverter))]
public class MasterData
{
public int Id { get; set; }
public long Seq { get; set; }
public List<InnerObjects> Obj { get; set; }
}
[JsonConverter(typeof(InnerObjectsConverter))]
public class InnerObjects
{
public string Id { get; set; }
public OrderData Data { get; set; }
}
public class OrderData
{
public string currencyPair { get; set; }
public List<Dictionary<string, string>> orderBook { get; set; }
}
class InnerObjectsConverter : JsonConverter
{
public override bool CanConvert(Type objectType)
{
return objectType == typeof(InnerObjects);
}
public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
{
var value = new InnerObjects();
value.Id = reader.ReadAsString();
reader.Read();
value.Data = serializer.Deserialize<OrderData>(reader);
reader.Read();
return value;
}
public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
{
throw new NotImplementedException();
}
}
class MasterDataConverter : JsonConverter
{
public override bool CanConvert(Type objectType)
{
return true;
}
public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
{
if (reader.TokenType == JsonToken.StartArray)
{
var value = new MasterData
{
Id = (int)reader.ReadAsInt32(),
Seq = (long)(decimal)reader.ReadAsDecimal()
};
reader.Read();
value.Obj = serializer.Deserialize<List<InnerObjects>>(reader);
reader.Read();
return value;
}
return null;
}
public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
{
throw new NotImplementedException();
}
}
应该添加对无效数据的一些额外处理，但这应该让你开始。
答案 1 :(得分：0)
这是一个非常令人讨厌的JSON格式。除了创建自己的序列化程序之外，您还可以手动选择和反序列化适当的子集。这种方法不太稳健，但有时可以更快地构建一次性方案。
static void Main(string[] args)
{
string json = @"[130, 18063676, [[""i"", {
""currencyPair"": ""XMR_BLK"",
""orderBook"": [{
""0.00229667"": ""22.10045806"",
""0.00229668"": ""2.24052467"",
""0.00230580"": ""0.66824024"",
// ...
}
]
}
]]]";
var outerArray = JArray.Parse(json);
var innerNestedArray = outerArray[2];
var iOrderBookArray = innerNestedArray[0];
var orderBookElement = iOrderBookArray[1];
var orderBook = orderBookElement.ToObject<OrderBook>();
var orderLines = orderBook.orderBook[0].ToList();
}
public class OrderBook
{
public string currencyPair { get; set; }
public Dictionary<string, string>[] orderBook { get; set; }
}