Question

我在django有这样的模特：

class Client(models.Model):
    type = (choices)

class Bill(models.Model):
    client = models.ForeignKey(Client)

class Detail(models.Model):
    total = models.MoneyField() # i used currency package
    bill = models.ForeignKey(Bill)

详细信息类包含Bill的销售详细信息，我已经在Bill.save（）方法中同时保存了账单和详细信息，但我想将Client.type从Bill.save（）传递给Detail。保存（），我想要那样的东西

def save(self, *args, **kwargs): #this is Bill save method
    client = self.Client
    transaction.atomic:
        super(Bill, self).save(*args, **kwargs)
        for detail in self.details
            detail.save(client)

def save(self, *args, **kwargs): #this is Detail save method
    self.pricing(client)
    super(Detail, self).save(*args, **kwargs)

def pricing(self, client):
    if client.type = 'value1':
        self.total = self.total - (self.total*5/100)
    elif client.type = 'value2':
        self.total = self.total - (self.total*7/100)
    else:
        self.total = self.total - (self.total*10/100)

我不知道传递参数如何在python和Django上运行，解决这个问题的最简洁的解决方案是什么？总之，我希望bill.save方法选择client.type值并通过detail.save传递它来计算总数和案例。

由于

Answer 1

您可以使用save方法在kwargs中传递参数尝试使用以下代码在另一个保存方法中传递客户端变量（detail.save(client=client)）并使用client = kwargs.get('client')

访问此变量

def save(self, *args, **kwargs): #this is Bill save method
    client = self.Client
    transaction.atomic:
        super(Bill, self).save(*args, **kwargs)
        for detail in self.details
            detail.save(client=client)

def save(self, *args, **kwargs): #this is Detail save method
    client = kwargs.get('client')
    self.pricing(client)
    super(Detail, self).save(*args, **kwargs)

这可能对你有帮助..

Answer 2

在您的情况下，您可以简单地使用自我属性：

def save(self, *args, **kwargs): #this is Detail save method
    self.pricing(self.bill.client)
    #           ^^^^^^^^^^^
    super(Detail, self).save(*args, **kwargs)

Django通过保存方法（模型）传递参数

2 个答案: