Question

我有两个相同代码的版本，一个短版本和一个长版本。我真的想使用短文，因为我不知道用户输入字典的值是多少。

所以长版本是：

angles_1= {'angle_1': 'abc', 'angle_2': 'acb', 'angle_3': 'cab'}
shared_vertex = 'c'
print(angles_1['angle_1'][1])
print(angles_1['angle_2'][1])
print(angles_1['angle_3'][1])
if shared_vertex == (angles_1['angle_1'][1]):
    print("{}".format(angles_1['angle_1']), 'is a vertically opposite angle')
elif shared_vertex == (angles_1['angle_2'][1]):
    print("{}".format(angles_1['angle_2']), 'is a vertically opposite angle')
elif shared_vertex == (angles_1['angle_3'][1]):
    print("{}".format(angles_1['angle_3']), 'is a vertically opposite angle')
else:
    print('There are no vertically opposite angles')

简短版本是：

loop = 3
for n in range(loop):
    def to_ordinal(n:int) -> str:
        endings = {1: "", 2: "", 3: ""}
    if shared_vertex == (angles_1['angle_{}'.format(to_ordinal(n))[1]]):
        print("{}".format(angles_1['angle_{}'.format(to_ordinal(n))]), 'is a vertically opposite angle')
    else:
        print("{}".format(angles_1['angle_{}'.format(to_ordinal(n))]), 'is not a vertically opposite angle')

现在短版本支持KeyError的错误。

我能帮忙吗？

Answer 1

你可以在相反的角度迭代角度和break：

angles_1= {'angle_1': 'abc', 'angle_2': 'acb', 'angle_3': 'cab'}
shared_vertex = 'c'

for vertices in angles_1.values():
    if vertices[1] == shared_vertex:
        print(vertices, 'is a vertically opposite angle')
        break
else:
    print('There are no vertically opposite angles')

我在循环上使用else子句，你可以阅读它here。

另一种方法是制作一个临时字典并.get一个角度：

angle = {a[1]: a for a in angles_1.values()}.get(shared_vertex)

if angle:
    print(angle, 'is a vertically opposite angle')
else:
    print('There are no vertically opposite angles')

Answer 2

我猜你几乎没有为你的词典和打印功能关闭括号。

更新的代码：

loop = 3
for n in range(loop):
    def to_ordinal(n:int) -> str:
        endings = {1: "", 2: "", 3: ""}
    if shared_vertex == (angles_1['angle_{}'.format(to_ordinal(n))][1]):
        print("{}".format(angles_1['angle_{}'.format(to_ordinal(n))]), 'is a vertically opposite angle')
    else:
        print("{}".format(angles_1['angle_{}'.format(to_ordinal(n))]), 'is not a vertically opposite angle')

如何在字典键中添加for循环？

2 个答案: