Question

请链接我任何教程或只是告诉我如何这样做，它只显示最近添加的新闻评论。我如何只选择一个？

<?php
                echo "<form action='".setComments($conn)."' method='post'>
                    <input type='hidden' name='username'><br>
                    <input type='hidden' name='date' value='".date('Y-m-d H:i:s')."'><br>
                    <label>Comment:<br> <textarea cols='50' rows='6' name='message' ></textarea></label><br>
                    <button type='submit' name='commentSubmit' class='btn btn-default'>Comment</button>
                    </form>";
                getComments($conn);
                ?>

                   <div class="comment_div">
                    <?php
                    $query = "SELECT * FROM comment order by date desc";
                    mysqli_query($conn,$query) or die("Error queryng db");
                    $result = mysqli_query($conn,$query);
                    while ($row = mysqli_fetch_array($result)){
                        $name = $row['name'];
                        $com = $row['comment'];
                        $date = $row['date'];
                        echo "
                            <div class='commentinfo'>
                            <p class='username'>სახელი: $name ; თარიღი: $date</p>
                            <p class='comment'>კომენტარი: <br> $com</p>
                            </div>
                            ";
                    }
                    ?>

在comments.php中：

<?php
function setComments($conn) {
    if (isset($_POST['commentSubmit'])) {
        $uid = $_POST['username'];
        $date = $_POST['date'];
        $message = $_POST['message'];

        $sql = "INSERT INTO comments (username,date,message) VALUES ('$uid','$date', '$message')";
        $result = mysqli_query($conn,$sql);
    }
}

function getComments ($conn) {
    $sql = "SELECT * FROM comments";
    $result = mysqli_query($conn,$sql);
    while ($row = mysqli_fetch_array($result)) {
        echo $row['username']."<br>";
        echo $row['date']."<br>";
        echo $row['message']."<br><br>";
    };
    echo "
        <form method='post' action'editcomment.php'>
            <input type='hidden' name='id' value='".$row['id']."'>
            <input type='hidden' name='username' value='".$row['username']."'>
            <input type='hidden' name='date' value='".$row['date']."'>
            <input type='hidden' name='message' value='".$row['message']."'>
            <button>შესწორება</button>
    ";

}

我想只显示发布评论的新闻，我要发布所有新闻评论其他新闻。

Answer 1

您需要在查询中使用LIMIT和ORDER BY标记，因此它看起来像这样：

$sql = "SELECT * FROM comments ORDER BY id DESC LIMIT 1";

此查询有两个新参数，我们需要按ID排序，以便我们可以获得降序（DESC用于什么），我们将数量限制为1;如果您需要更多，可以更改号码。

如果您要提取特定项目，可以在查询中使用WHERE子句：WHERE id = #call for id#

为了确保评论仅出现在文章中，您需要为评论创建某种标识符行并在帖子中进行比较：

// get the post ID from the database
$post_id = $row['id'];

// now that you have the post id, and assuming you have an identifier add the WHERE clause
$sql = "SELECT * FROM comments WHERE comment_post_id = " . $post_id;

要在他们输入评论时添加comment_post_id添加，请从他们所在的当前帖子中添加。

因此，如果您的帖子id为12，那么该帖子中的评论应该将comment_post_id等于12。

Answer 2

您的选择查询缺少where子句。它应该看起来像。

$sql ="select  * from comments where news_id='".$news_id."';

PHP评论新闻只有一条新闻

2 个答案: