Question

它在底部跳过if Ctype == 1（2，3等），不明白为什么。

print("Starting game.")
print("Game Started.")
print('\n')
CharName = input('Create a character name: ')
print('\n' * 20)
print('Class Selection: (Ensure it as written as you read it)')
print('\n')
print('Classes:')
print('[1] Heavy')
print('[2] LightFooted')
print('[3] Warrior')
print('\n')
print('To Come:')
print('Stealth')
print('\n')
Ctype = input('Choose class: ')
if Ctype == 1:
    print('test')
if Ctype == 2:
    print('test')
if Ctype == 3:
    print('test')
if Ctype == 4:
    print('Try again... another time.')
    time.wait(2)

Answer 1

input()在Python3中返回一个字符串。

所以Ctype是一个字符串。然后比较一个整数，因此等式检查失败。

将字符串转换为int，如下所示：

Ctype = int(Ctype)

Python被忽略了

1 个答案: