我有一个MariaDB 10.2.8数据库,我用它来存储特定根目录下所有文件的爬网结果。所以文件(在directory
表中)有一个父目录(在/home
表中)。此父目录可能有自己的父目录,依此类推,直到目录爬网开始的原始点。
因此,如果我从/home/tim/projects/foo/bar.py
进行了抓取,则文件foo
将具有父目录projects
,该目录将具有父目录/home
,依此类推。 null
(抓取的根目录)将拥有with recursive tree as (
select id, name, parent from directory where id =
(select parent from file where id = @FileID)
union
select d.id, d.name, d.parent from directory d, tree t
where t.parent = d.id
) select name from tree;
个父级。
我得到了以下递归CTE:
@FileID
(按预期方式)按顺序返回结果,其中Welcome to the MariaDB monitor. Commands end with ; or \g.
Your MariaDB connection id is 17
Server version: 10.2.8-MariaDB-10.2.8+maria~jessie-log mariadb.org binary distribution
Copyright (c) 2000, 2017, Oracle, MariaDB Corporation Ab and others.
Type 'help;' or '\h' for help. Type '\c' to clear the current input statement.
MariaDB [(none)]> use inventory;
Reading table information for completion of table and column names
You can turn off this feature to get a quicker startup with -A
Database changed
MariaDB [inventory]> with recursive tree as (
-> select id, name, parent from directory where id =
-> (select parent from file where id = 3790)
-> union
-> select d.id, d.name, d.parent from directory d, tree t
-> where t.parent = d.id
-> ) select name from tree;
+----------+
| name |
+----------+
| b8 |
| objects |
| .git |
| fresnel |
| Projects |
| metatron |
+----------+
6 rows in set (0.00 sec)
MariaDB [inventory]> Bye
tim@merlin:~$
是文件的主键。 e.g。
/metatron/Projects/fresnel/.git/objects/b8
因此,在这种情况下,文件ID 3790对应目录/metatron
中的文件(order by id
当然是爬网的根目录。)
是否有一种可靠的方法来反转输出的顺序(因为我想将它连接在一起以产生完整的路径)。我可以{{1}}但这并不可靠,因为即使我知道,在这种情况下,孩子的身份证明会比他们的父母更高,但我无法保证这种情况始终如此。在任何情况下我都想使用CTE。
答案 0 :(得分:-1)
(
your-current-query
) ORDER BY ...;
(如果您遇到问题,请将SELECT ...
放在前面。