在Javascript抛出错误中解析Laravel JSON对象

Question

Laravel代码：

$teachers = Teachers::where('possessed_by_community', $communityId)->pluck('teacher_name');

return view('pages.show_add_teachers', [
    'teachers'  => $teachers
]);

然后在客户端我尝试了：

var teachers = "<?php echo json_encode($teachers) ?>" ;
teachers = JSON.parse(teachers);
console.log(teachers);

在网络控制台中，我得到：

SyntaxError: missing ; before statement

在firefox调试器中：

Answer 1

使用单引号代替var teachers = '<?= json_encode($teachers) ?>';

或根本不使用引号，省略JSON.parse(teachers);。

var teachers = <?= json_encode($teachers) ?>;
console.log(teachers);

虽然您必须始终检查$teachers是否有效，字符串，null或数组。

否则它会变成var teachers = ;并且会中断。

Answer 2

var jArray = @json($teachers);