Question

如果我有

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如何在没有中间附加变量的情况下设置这样的结果。

x = 5;
y = 6;

Answer 1

1）只能使用数学运算，你可以这样做。将总和保存到第一个变量中。然后在第二个中保持总和与当前值的差值，这将给出第一个值。在第一个变量之后，保持sum和seconds值的差值，这将给出第一个值。

＆＃13;

let x = 5;
let y = 6;

console.log(`x is ${x}, y is ${y}`);

x = x + y;
y = x - y;
x = x - y;

console.log(`x is ${x}, y is ${y}`);

＆＃13;

2）使用语言功能，您可以通过 Array Destructuring 来完成。

＆＃13;

let x = 5;
let y = 6;

console.log(`x is ${x}, y is ${y}`);

[x, y] = [y, x];

console.log(`x is ${x}, y is ${y}`);

＆＃13;

3）如果数字是整数，请使用着名的XOR swap algorithm。

＆＃13;

let x = 5;
let y = 6;

console.log(`x is ${x}, y is ${y}`);

x = x ^ y;
y = x ^ y;
x = x ^ y;

console.log(`x is ${x}, y is ${y}`);

＆＃13;

Answer 2

使用es2015，你可以

[x，y] = [y，x]

Answer 3

1）您可以使用第三个变量来交换x和y值。所以，如果第三个变量是temp。

第一步 temp = x

第二步 x = y

第3步 y = temp

 var x = 5;
 var y = 6;
 var temp = 0;

  temp = x;
  x = y;
  y = temp;

  console.log('x =',x);
  console.log('y =',y);

2） ES6

var x = 5,
    y = 6;

[x, y] = [y, x];

console.log('x =', x, 'y =', y);

js将x变量设置为y而不使用额外变量

3 个答案: