Question

如何做到这一点，这个函数会在表格中寻找一行而不是给定名称 John ，而是通过输入 'name' ？

public function validation($request)
{
    return $this->validate($request, [
        'name' => 'required|max:255',
        'last_name' => 'required|max:255',
        'code' =>  ['required',Rule::exists('users')->where(function ($query) {
            $query->where('name', '=', 'John');

        }), ],
    ]);
}

Answer 1

检查你的参数并改变约翰＆＃39;要求 - >名称

＆＃13;

public function validation(Request $request){
  return $this->validate($request, [
          'name'      => 'required|max:255',
          'last_name' => 'required|max:255',
          'code'      => [
                          'required',
                          Rule::exists('users')
                              ->where('name', $request->name)
                        ],
        ]);
}

＆＃13;

Answer 2

您必须使用use关键字并将$request对象传递到此内容

public function validation($request)
{
    return $this->validate($request, [
        'name' => 'required|max:255',
        'last_name' => 'required|max:255',
        'code' =>  ['required',Rule::exists('users')->where(function ($query) use ($request) {
            $query->where('name', '=', $request->name);

        }), ],
    ]);
}

或者，您可以使用这样的方法，而不会在where中传递回调函数

public function validation($request)
{
    return $this->validate($request, [
        'name' => 'required|max:255',
        'last_name' => 'required|max:255',
        'code' =>  array('required',Rule::exists('users')->where('name', '=', $request->name);),
    ]);
}

Laravel验证自定义规则

2 个答案: