我如何从null JSONObject获取数据?

时间:2017-09-09 05:40:13

标签: java android json exception-handling

这是我关于StackOverflow的第一个问题,很抱歉这个问题表达不好。

以下是logcat中的Json:

I/Result is: null{"coord":{"lon":-0.13,"lat":51.51},"weather":[{"id":300,"main":"Drizzle","description":"light intensity drizzle","icon":"09d"}],"base":"stations","main":{"temp":280.32,"pressure":1012,"humidity":81,"temp_min":279.15,"temp_max":281.15},"visibility":10000,"wind":{"speed":4.1,"deg":80},"clouds":{"all":90},"dt":1485789600,"sys":{"type":1,"id":5091,"message":0.0103,"country":"GB","sunrise":1485762037,"sunset":1485794875},"id":2643743,"name":"London","cod":200}

这是我的代码:

public class MainActivity extends AppCompatActivity {
    String weather,id,result;

    public class DownloadTask extends AsyncTask<String,Void,String>{

        @Override
        protected String doInBackground(String... urls) {
            try {
                URL url = new URL(urls[0]);
                HttpURLConnection httpURLConnection = (HttpURLConnection) url.openConnection();
                InputStream inputStream = httpURLConnection.getInputStream();
                InputStreamReader inputStreamReader = new InputStreamReader(inputStream);
                int data = inputStreamReader.read();

                while(data != -1){
                    char count = (char) data;
                    result += count;
                    data = inputStreamReader.read();
                }

                return result;

            } catch (MalformedURLException e) {
                e.printStackTrace();
            } catch (IOException e) {
                e.printStackTrace();
            }
            return null;
        }

        @Override
        protected void onPostExecute(String result) {
            super.onPostExecute(result);

           try {
                JSONObject jsonObject = new JSONObject(result);

                 String res = jsonObject.getString("coord");

                Log.i("Result is ",res);
            } catch (JSONException e) {
                e.printStackTrace();
           }


        }
    }

    @Override
    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_main);

       // Toast.makeText(this, id, Toast.LENGTH_SHORT).show();

        DownloadTask task = new DownloadTask();
        task.execute("http://samples.openweathermap.org/data/2.5/weather?q=London,uk&appid=b1b15e88fa797225412429c1c50c122a1");

    }
}

这是例外:

  

W / System.err:org.json.JSONException:类型的null null   org.json.JSONObject $ 1无法转换为JSONObject

1 个答案:

答案 0 :(得分:5)

使用空

初始化结果字符串
String result="";

您的结果String是类变量,默认情况下所有String都是使用 =null 值初始化

以下行添加到 null+yourResponse

 result += count;