Question

如何使此解析器更高效？我觉得这些陈述是疯狂的！我认为回调函数能够完成工作。但是，我的大多数标识符都大不相同，我需要经历许多不同的密钥。我应该创建一个标签数组和一个DOM元素数组，并为每个元素创建一个回调函数来去除空值？我是第一次尝试拼凑刮刀，而且我真的被这里的逻辑所困扰。

任何帮助都会受到重视！

cout << "Enter your name: ";
cin >> MyClass.setName();
cout << "\nHello, " << MyClass.getName();
// although this isn't exactly how it'll be used in-program

我觉得我可以做这样的事情

foreach($html->find('.b-card') as $article) {
    $data[$y]['business']     = $article->find('h1', 0)->plaintext;
    $data[$y]['address']      = $article->find('.address', 0)->plaintext;

    if($article->find('.phone-num', 0)) {
      $data[$y]['phone']      = $article->find('.phone-num', 0)->plaintext;
    } else {
       $data[$y]['phone']     = 'Number not listed.';
    }

    if($article->find('.link', 0)) {
      $data[$y]['website']    = $article->find('.link', 0)->plaintext;
    } else {
       $data[$y]['website']   = 'Website not listed.';
    }
    if($article->find('.established', 0)) {
      $data[$y]['years']    = str_replace("\r\n","",$article->find('.established', 0)->plaintext);
    } else {
       $data[$y]['years']   = 'Years established not listed.';
    }
    if($article->find('.open-hours', 0)) {
      $data[$y]['hours']    = $article->find('.open-hours', 0)->plaintext;
    } else {
       $data[$y]['hours']   = 'Hours not listed.';
    }
    if($article->find('.categories a', 0)) {
      $data[$y]['category']    = $article->find('.categories a', 0)->plaintext;
    } else {
       $data[$y]['category']   = 'Category not listed.';
    }

    $articles[] = $data[$y];
}

}

Answer 1

使用一个数组收集每个if块中的所有相关信息。

$selector_list = array(
    array('selector' => '.phone-num', 'index' => 'phone', 'name' => 'Number'),
    array('selector' => '.link', 'index'' => 'website', 'name' => 'Website'),
    array('selector' => 'open-hours', 'index' => 'hours', 'name' => 'Hours'),
    array('selector' => '.categories a', 'index' => 'category', 'name' => 'Category')
);

然后，您可以使用包含所有常用代码的简单foreach循环：

foreach ($selector_list as $sel) {
    $found = $article->find($sel['selector'], 0);
    if ($found) {
        $data[$y][$sel['index']] = $found;
    } else {
        $data[$y][$sel['index']] = $sel['name'] . " not listed.";
    }
}
// Special case for selector that doesn't follow the same pattern
$found = $article->find('.established', 0);
if ($found) {
    $data[$y]['years'] = str_replace("\r\n", "", $found);
} else {
    $data[$y]['years'] = Years established not listed.';
}

如果您希望循环能够处理需要特殊处理的循环，您可以向数组添加回调函数。但如果它只是一个奇怪的情况，那可能是矫枉过正的。

如何使用嵌套数组使这个PHP DOM解析器更高效？

1 个答案: