标签: python python-3.x
a = [[1,2,3,4],[5,6],[7,8,9]] 至 name_doesn't_matter = [[11,12,13,14],[15,16],[17,18,19]]
a = [[1,2,3,4],[5,6],[7,8,9]]
name_doesn't_matter = [[11,12,13,14],[15,16],[17,18,19]]
并且子列表的数量是用户输入的结果,因此答案应该是针对任何给定数量的子列表。
答案 0 :(得分:2)
使用列表推导:
foo = [[1, 2, 3, 4], [5, 6], [7, 8, 9]] bar = [[x + 10 for x in inner] for inner in foo]