Question

我正在编写一个脚本来读取状态文件以记录设备的状态。该文件遵循这种规则＆＃39;：第一行是＆＃34; [ACTIVE_JOB]＆＃34;其次是每行列出的乔布斯。然后，有一行说＆＃34; [COMPLETE_JOB]＆＃34;然后是每行上列出的作业。在该列表的最后，它涉及到我不关心的其他一些东西，但是其他东西的第一行＆＃39;总是以＆＃34; [＆＃34;开头。所以这就是交易，当我把东西推到一个数组中，然后对阵列进行拆分时，如果没有活动作业，它似乎将第一个完成的作业推入活动作业数组。我只是想创建一个活动作业和已完成作业的列表或数组，但是当没有活动作业时它会绊倒我。

无论如何，这里是我正在研究的snippit（您可以取消注释PATH变量集以在测试文件读取之间交替，如果这样可以更容易）：

#$Path = 'C:\Scripts\NoJOBS.txt'
#$Path = 'C:\Scripts\NoActiveJobs.txt'
#$Path = 'C:\Scripts\ManyJobs.txt'
$StatusFile = Get-Content $path ##  Reads the Status File as an array
#$StatusArray = @()
#$ActiveJobs = @()
#$CompleteJobs = @()
$StatusArray = New-Object System.Collections.ArrayList
$ActiveJobs = New-Object System.Collections.ArrayList
$CompleteJobs = New-Object System.Collections.ArrayList

foreach ($Line in $StatusFile) {
if ($Line -like "*PUBLISHER*") {Break}
#$StatusArray += $Line
$StatusArray.Add($Line)
}
$Seperator = "[ACTIVE_JOB]","[COMPLETE_JOB]"
$ActiveJobs,$CompleteJobs = $StatusArray.Split($Seperator,2,[System.StringSplitOptions]::RemoveEmptyEntries)
#$ActiveJobs = [System.Collections.ArrayList]$ActiveJobs
#$CompleteJobs = [System.Collections.ArrayList]$CompleteJobs
foreach ($Job in $ActiveJobs) {
    #if($job.Contains("[")){ $ActiveJobs.Remove($Job) }
    if($job.Contains("[")){ $ActiveJobs = $ActiveJobs | ? {$_ -ne $job} }

}
foreach ($Job in $CompleteJobs) {
    #if($job.Contains("[")){ $CompleteJobs.Remove($Job) }
    if($job.Contains("[")){ $CompleteJobs = $CompleteJobs | ? {$_ -ne $Job } }

}

如果没有作业，这就是文件的内容（另存为NoJOBS.txt）：

[ACTIVE_JOB]
[COMPLETE_JOB]
[PUBLISHER1]
NAME=PP-50 1
STACKER1=62
STACKER2=9
STACKER3=0

如果有1个已完成的作业，但没有活动作业（另存为NoActiveJobs.txt），则说明如下：

[ACTIVE_JOB]
[COMPLETE_JOB]
JOB1=Frank_L_Smith-085149-08092017
[Frank_L_Smith-085149-08092017]
STATUS=99

最后，这里有1个活动作业和许多已完成的作业（Save as ManyJobs.txt）：

[ACTIVE_JOB]
JOB1=April_Ztest-124856-31082017
[COMPLETE_JOB]
JOB1=Mel_R_Smith-141307-31082017
JOB2=Mel_R_Smithe-132029-31082017
JOB3=Melvin_R_Smithy-131037-31082017
JOB5=Will_R_Smith-123534-31082017
[Mel_R_Smith-141307-31082017]
PUBLISHER=PP-50 1
STATUS=4
PUBLICATION_NUMBER=1
COMPLETION_NUMBER=1
ERRORDISC_NUMBER=0

在Win10上使用PSVersion 5.1.14393.1066和.NET 4.7

Answer 1

从TheScritpingGuy添加了这个功能，它就像一个魅力！谢谢@BenH !!

Function Get-IniContent {  
    <#  
    .Synopsis  
        Gets the content of an INI file  

    .Description  
        Gets the content of an INI file and returns it as a hashtable  

    .Notes  
        Author        : Oliver Lipkau <oliver@lipkau.net>  
        Blog        : http://oliver.lipkau.net/blog/  
        Source        : https://github.com/lipkau/PsIni 
                      http://gallery.technet.microsoft.com/scriptcenter/ea40c1ef-c856-434b-b8fb-ebd7a76e8d91 
        Version        : 1.0 - 2010/03/12 - Initial release  
                      1.1 - 2014/12/11 - Typo (Thx SLDR) 
                                         Typo (Thx Dave Stiff) 

        #Requires -Version 2.0  

    .Inputs  
        System.String  

    .Outputs  
        System.Collections.Hashtable  

    .Parameter FilePath  
        Specifies the path to the input file.  

    .Example  
        $FileContent = Get-IniContent "C:\myinifile.ini"  
        -----------  
        Description  
        Saves the content of the c:\myinifile.ini in a hashtable called $FileContent  

    .Example  
        $inifilepath | $FileContent = Get-IniContent  
        -----------  
        Description  
        Gets the content of the ini file passed through the pipe into a hashtable called $FileContent  

    .Example  
        C:\PS>$FileContent = Get-IniContent "c:\settings.ini"  
        C:\PS>$FileContent["Section"]["Key"]  
        -----------  
        Description  
        Returns the key "Key" of the section "Section" from the C:\settings.ini file  

    .Link  
        Out-IniFile  
    #>  

    [CmdletBinding()]  
    Param(  
        [ValidateNotNullOrEmpty()]  
        [ValidateScript({(Test-Path $_) -and ((Get-Item $_).Extension -eq ".txt")})]  
        [Parameter(ValueFromPipeline=$True,Mandatory=$True)]  
        [string]$FilePath  
    )  

    Begin  
        {Write-Verbose "$($MyInvocation.MyCommand.Name):: Function started"}  

    Process  
    {  
        Write-Verbose "$($MyInvocation.MyCommand.Name):: Processing file: $Filepath"  

        $ini = @{}  
        switch -regex -file $FilePath  
        {  
            "^\[(.+)\]$" # Section  
            {  
                $section = $matches[1]  
                $ini[$section] = @{}  
                $CommentCount = 0  
            }  
            "^(;.*)$" # Comment  
            {  
                if (!($section))  
                {  
                    $section = "No-Section"  
                    $ini[$section] = @{}  
                }  
                $value = $matches[1]  
                $CommentCount = $CommentCount + 1  
                $name = "Comment" + $CommentCount  
                $ini[$section][$name] = $value  
            }   
            "(.+?)\s*=\s*(.*)" # Key  
            {  
                if (!($section))  
                {  
                    $section = "No-Section"  
                    $ini[$section] = @{}  
                }  
                $name,$value = $matches[1..2]  
                $ini[$section][$name] = $value  
            }  
        }  
        Write-Verbose "$($MyInvocation.MyCommand.Name):: Finished Processing file: $FilePath"  
        Return $ini  
    }  

    End  
        {Write-Verbose "$($MyInvocation.MyCommand.Name):: Function ended"}  
}

Powershell Array拆分错误的顺序

1 个答案: