Question

我有一个网站，允许用户从单选按钮中选择测试脚本，并在使用PHP将所需测试提交到远程服务器之后：

它在test_activity_log表中插入一行到MySQL数据库，包含id，username，test name，gateway name和timestamp。
然后发送ssh2_exec以在远程网关上执行所需的脚本

上面的所有内容我已经有了工作，但是，当多个用户同时从网页执行脚本时，我需要找到一种方法来按顺序排列它们并一个接一个地执行它们。最好的方法是什么？

非常感谢任何想法。

编辑：

testexe.php

<?php

...
...    

//while there are still jobs that are not done..
while (1) {
    //wait for 10 seconds and query again...
    sleep(10);
    $statusResult = mysqli_query($dbConnection, $qStatus);
    //if there are undone jobs we pick them and execute them
    if (mysqli_num_rows($statusResult) > 0){
        //query the next undone test case
        $testResult = mysqli_query($dbConnection, $qNextTest);

        //fetch the returned query object and store needed parameters 
        $row = $testResult->fetch_assoc();
        $id = $row['id'];               
        $test_script = $row['test_script']; 
        $gateway = $row['gateway'];         


        if ($connection = @ssh2_connect($gateway, 22)) {
            ssh2_auth_password($connection, $user, $password);

            //execute the test case
            $stream = ssh2_exec($connection, "/my/path/to/script.sh"); 

            //fetch output stream and stderr
            stream_set_blocking($stream, true);
            $stream_out = ssh2_fetch_stream($stream, SSH2_STREAM_STDIO);
            $stream_err = ssh2_fetch_stream($stream, SSH2_STREAM_STDERR);
            while($line = fgets($stream_out)) {flush(); echo '<pre>' . $line . '</pre>';}               
            echo '<pre>' . "------------------------\n" . '</pre>';
            while($line = fgets($stream_err)) {flush(); echo '<pre>' . $line . '</pre>';}
            fclose($stream);    

            //update the table after the above script is done
            $qUpdateStatus = "UPDATE table SET status = 1 WHERE id = $id";
            $updateresult = mysqli_query($dbConnection, $qUpdateStatus);
        }

    }
}

?>

使用PHP和MySQL按顺序执行脚本

0 个答案: