Question

我试图根据属性文件中的布尔值有条件地在XML DSL中启动路由。但它有点不起作用。我不确定这是不是正确的做法。任何帮助表示赞赏，谢谢:)

这是我的blueprint.xml

<bean id="bridgePropertyPlaceholder" class="org.apache.camel.spring.spi.BridgePropertyPlaceholderConfigurer">
    <property name="location" value="classpath:property.properties"/>
</bean>

<camelContext id="camel" xmlns="http://camel.apache.org/schema/spring">


    <route autoStartup="${isTrue}">
        <from uri="pipe:prs:P" />
        <choice>
            <when>
                <simple>${headers.headerName} == 'DR91'</simple>
                <process ref="reqType"></process>
                <to uri="direct-vm:pipeRequestDR91" />
            </when>
            <when>
                <simple>${headers.headerName} == 'DR93'</simple>
                <process ref="reqType"></process>
                <to uri="direct-vm:pipeRequestDR93" />
            </when>
        </choice>
    </route>

这是我的属性文件 - property.properties

isTrue=true

我得到的错误说：

org.apache.camel.RuntimeCamelException: 
org.apache.camel.FailedToCreateRouteException: Failed to create route 
route1: Route(route1)[[From[pipe:prs:P]] -> [Choice[[When[simple{${h... 
because of Error parsing [${isTrue}] as a Boolean.

Answer 1

您应该使用Camel的属性占位符语法{{xxx}}，例如

 <route autoStartup="{{isTrue}}">

Answer 2

我认为这还不支持。看这里 http://camel.apache.org/how-do-i-use-spring-property-placeholder-with-camel-xml.html

从XML DSL动态启动camel路由

2 个答案: