R中的igraph - 合并两个图

Question

我正在尝试使用igraph合并R中的两个图形。理想情况下，我会创建g1和g2的顶点联合，仅保留g1的边。应该基于label属性创建此联合。我想我可以在合并之前简单地从g2删除所有边缘，使用类似这样的东西：

g2 %>% delete_edges(seq(1, length(E(g2)), by = 1))

但是，当我创建一个这样的联盟时：

g.union <- graph.union(g1, g2, byname=F)

我得到的图表包含属性id_1，id_2，label_1，label_2，weight_1，weight_2 ...这不是我想要的。我需要保留g1中的所有顶点和边，只添加g2中g1中缺少的g1个顶点。保留那些添加顶点的所有属性。

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修改

@MrFlick，我无法分享这些图表，但一个简单的例子是这样的：

我有graph [ directed 1 node [ id 1 label "it2igcryfm862x" mydetails "somedetails1" ] node [ id 2 label "it0l2xa53eu1w3" mydetails "somedetails2" ] node [ id 3 label "iszyxcopnao380" mydetails "somedetails3" ] edge [ source 1 target 2 weight 1 ] edge [ source 1 target 3 weight 2 ] edge [ source 2 target 3 weight 1 ] ]

g2

和graph [ directed 1 node [ id 1 label "it2igcryfm862x" mydetails "somedetails1" ] node [ id 2 label "it0l2xa53eu1w3" mydetails "somedetails2" ] node [ id 3 label "iszyxcopnao380" mydetails "somedetails3" ] node [ id 4 label "it0lhztmkln4n6" mydetails "somedetails4" ] edge [ source 1 target 2 weight 1 ] edge [ source 1 target 3 weight 3 ] edge [ source 2 target 3 weight 2 ] edge [ source 2 target 4 weight 2 ] edge [ source 3 target 4 weight 1 ] ]

g3

我需要的是graph [ directed 1 node [ id 1 label "it2igcryfm862x" mydetails "somedetails1" ] node [ id 2 label "it0l2xa53eu1w3" mydetails "somedetails2" ] node [ id 3 label "iszyxcopnao380" mydetails "somedetails3" ] node [ id 4 label "it0lhztmkln4n6" mydetails "somedetails4" ] edge [ source 1 target 2 weight 1 ] edge [ source 1 target 3 weight 2 ] edge [ source 2 target 3 weight 1 ] ]

def handle_click(event):
    if treeview.identify_region(event.x, event.y) == "separator":
        return "break"

#...

treeview.bind('<Button-1>', handle_click)

Answer 1

这是一个可重现的例子

library(igraph)
set.seed(1)
g1 <- make_(ring(10), with_vertex_(label = LETTERS[1:10]))
V(g1)$color = "red"
g2 <- make_(ring(15), with_vertex_(label = LETTERS[1:15]))
V(g2)$color <- "cyan"

你需要

  

保留g1中的所有顶点和边，只添加那些顶点   来自g2中缺少的g1。保持那些添加的所有属性   顶点。

一种方法：

v <- V(g2)[!V(g2)%in%V(g1)]
g3 <- add_vertices(g1, length(v), attr = vertex.attributes(g2, v))

以下是两张原始图表和结果的样子：

par(mfrow=c(1,3))
lapply(mget(ls(pattern = "^g\\d")), plot)

Answer 2

您的原始代码似乎接近于您提供的示例。

library(igraph)

###  Recreating your example
par(mfrow = c(2,2), mar=c(0.5,0.5,0.5,0.5))
g1 = graph_from_edgelist(matrix(c(1,2,1,3,2,3), ncol=2, byrow=TRUE))
g1 = set_vertex_attr(g1, "label", 
    value=c("it2igcryfm862x", "it0l2xa53eu1w3", 
        "iszyxcopnao380"))
plot(g1)
box()

g2 = graph_from_edgelist(matrix(c(1,2,1,3,2,3,2,4,3,4), ncol=2, byrow=TRUE))
g2 = set_vertex_attr(g2, "label", 
    value=c("it2igcryfm862x", "it0l2xa53eu1w3", 
        "iszyxcopnao380", "it0lhztmkln4n6"))
plot(g2)
box()

## Create the desired union
g1g2 = union(g1,delete_edges(g2, E(g2)))

## Edit: Preserving labels
NewLabels = c(vertex_attr(g1, "label"), 
    setdiff(vertex_attr(g2, "label"), vertex_attr(g1, "label")))
g1g2 = set_vertex_attr(g1g2, "label", value=NewLabels)

plot(g1g2)
box()