Question

为什么我不能在此脚本中创建总单词总和？我得到的结果如下：

 120+130

但它不是250（正如我预期的那样）！有什么理由吗？

#!/bin/bash

while [ -z "$count" ] ;
do
    echo -e "request :: please enter file name "
    echo -e "\n\tfile one : \c"
    read count

    itself=counter.sh

    countWords=`wc -w $count |cut -d ' ' -f 1`
    countLines=`wc -l $count |cut -d ' ' -f 1`
    countWords_=`wc -w $itself |cut -d ' ' -f 1`

    echo "Number of lines: " $countLines
    echo "Number of words: " $countWords
    echo "Number of words -script: " $countWords_

    echo "Number of words -total " $countWords+$countWords_  

done

if [ ! -e $count ] ; then
    echo -e "error :: file one $count doesn't exist. can't proceed."
    read empty
    exit 1
fi

Answer 1

echo“单词数量 - 总数” $ countWords + $ countWords _

你想要这个：

echo "Number of words -total $((countWords + countWords_))"

修改

以下是对脚本的一些优化。

while循环似乎毫无意义因为count将被设置为确定里面做这个 1循环while循环。
您的if检查是否存在文件应该在你之前发生使用该文件。
您无需将脚本名称硬编码到变量itself，您可以使用$0
由于您使用的是bash，我冒昧地通过使用流程替换来消除对cut的需求。

以下是修订后的脚本：

#!/bin/bash

echo -e "request :: please enter file name "
echo -e "\n\tfile one : \c"
read count

if [ ! -e "$count" ] ; then
    echo "error :: file one $count doesn't exist. can't proceed."
    exit 1
fi

itself="$0"

read countWords _ < <(wc -w $count)
read countLines _ < <(wc -l $count)
read countWords_ _ < <(wc -w $itself)

echo "Number of lines: '$countLines'"
echo "Number of words: '$countWords'"
echo "Number of words -script: '$countWords_'"

echo "Number of words -total $((countWords + countWords_))"

Answer 2

解决这个问题的一种方法是：

echo `expr $countWords + $countWords_`

在shell脚本中求和

2 个答案:

修改