我可以查看下面点击了哪个按钮:
但我需要做的是通过ajax回调,如果我得到值'Y'或'N'然后设置检查单选按钮。请帮我解决这个问题。
$('input').iCheck({
checkboxClass: 'icheckbox_minimal',
radioClass: 'iradio_minimal',
increaseArea: '20%' // optional
});
$('input[type=radio][name=kitchen]').on('ifChecked', function() {
if (this.value === "N") {
alert('No');
} else {
alert('Yes');
}
});
<script src="https://ajax.googleapis.com/ajax/libs/jquery/3.1.1/jquery.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/iCheck/1.0.2/icheck.js"></script>
<link href="https://cdnjs.cloudflare.com/ajax/libs/iCheck/1.0.2/skins/all.css" rel="stylesheet" />
<div class="checkbox">
<label>Is Kitchen <input type="radio" name="kitchen" value="Y" class="flat">
Yes <input type="radio" name="kitchen" value="N" class="flat"> No
</label>
</div>
答案 0 :(得分:1)
进行ajax调用,然后在回调中检查返回的数据并使用iCheck()
函数检查所需的元素。
示例:
$.get('url', {}, function( data ){
if ( data === "Y" ){
$(':radio[name=kitchen][value=Y]').iCheck('check');
} else {
$(':radio[name=kitchen][value=N]').iCheck('check');
}
});
希望这有帮助。
$('input').iCheck({
checkboxClass: 'icheckbox_minimal',
radioClass: 'iradio_minimal',
increaseArea: '20%' // optional
});
var data = "N";
if ( data === "Y" ){
$(':radio[name=kitchen][value=Y]').iCheck('check');
} else {
$(':radio[name=kitchen][value=N]').iCheck('check');
}
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<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<script src="https://cdnjs.cloudflare.com/ajax/libs/iCheck/1.0.2/icheck.js"></script>
<link href="https://cdnjs.cloudflare.com/ajax/libs/iCheck/1.0.2/skins/all.css" rel="stylesheet" />
<div class="checkbox">
<label>Is Kitchen <input type="radio" name="kitchen" value="Y" class="flat">
Yes <input type="radio" name="kitchen" value="N" class="flat"> No
</label>
</div>
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