当我选择数据时,它会以
之类的格式填充输入 DD/MM/YYYY
但我需要通过表单发送数据, 当我在我的组件上执行console.log时
datapicker.component.ts
onFindAWhip(form: NgForm){
const value = form.value;
console.log(value);
}
我得到像
这样的完整日期Thu Sep 28 2017 00:00:00 GMT+0100 (GMT Daylight Time)
我是否必须重新格式化?
已经在我的DateAdapter中完成了,我已经尝试从这里获取它,但我只是得到错误
import { NativeDateAdapter } from '@angular/material';
export class MyDateAdapter extends NativeDateAdapter {
format(date: Date, displayFormat: Object): string {
let day = date.getDate();
let month = date.getMonth();
let year = date.getFullYear();
if (displayFormat == "input") {
let pickupData = date.toDateString();
let pickupDataArray = pickupData.split(" ");
let yearPicked = pickupDataArray[3];
const without = pickupData.substring(0, pickupData.length-4);
return without + ' '+yearPicked ;
} else if (displayFormat == "input-home") {
return this._to2digit(day) + '/' + this._to2digit(month) +'/'+ year;
}
else{
return date.toDateString();
}
}
private _to2digit(n: number) {
return ('00' + n).slice(-2);
}
}
datapicker.html
<span class="calendar-to">
<button md-raised-button (click)="pickupTo.open()" class="search--icon"></button>
<input [mdDatepicker]="pickupTo"
placeholder="DD/MM/YYYY"
name="date_to"
ngModel>
<md-datepicker touchUi="true" #pickupTo></md-datepicker>
</span>
答案 0 :(得分:1)
这是因为ngModel是一个DateTime,并包含所有那些信息。如果您只想要DD/MM/YYYY
,则必须在component.ts中处理它。您实际上只需在组件中使用Angular's DatePipe即可快速轻松地为您执行此操作。
导入管道:
import { DatePipe } from '@angular/common'
构建访问权限:
constructor( private datePipe: DatePipe ) { }
在方法中使用:
onFindAWhip(form: NgForm){
const value = form.value;
console.log(this.datePipe.transform(value, 'MM/dd/y'));
}