这是我第一次在这里提问,所以我希望我不犯任何错误...... 我正在做一个服务器 - 客户端程序,当我运行客户端时,我有这个错误,我有"核心转储错误"。
我想我知道错误在哪里,但我不知道如何解决它。 我有2个结构:
typedef struct {
int pid;
int cmd; //1 -login,2-registrar,3-tecla
char login[100];
char pw[100];
int tecla;
} PEDIDO;
typedef struct {
int cmd;
int res;
BONECO *b;
} RESPOSTA;
服务器通过命名管道向客户端发送数据时的代码:
int main(int argc, char *argv[], char *envp[]){
//...
i = read(fd, &p, sizeof (p));
printf(">>> Li %d bytes\n", i);
printf("User : %s PID : %d\n", p.login, p.pid);
if (p.cmd == 1) { //LOGIN
char user_fd[100], pw_fd[100];
FILE *f = fopen(argv[1], "r");
if (!f) {
printf("Erro ao abrir ficheiro\n");
exit(0);
}
while ((fscanf(f, "%s %s ", user_fd, pw_fd))) {
if (strcmp(p.login, user_fd) == 0 && strcmp(p.pw,pw_fd) == 0) {
printf("\nLOGIN CORRECTO!!!\n");
for (i = 0; i < 20; i++) {
if (clientes[i][0] != p.pid && clientes[i][0] == -1) {
clientes[i][0] = p.pid;
break;
}
}
sprintf(cli_fifo, "ccc%d", p.pid);
fd_resp = open(cli_fifo, O_WRONLY);
r.cmd = 1;
r.res = 1;
i = write(fd_resp, &r, sizeof (r));
close(fd_resp);
fclose(f);
break;
}
//...
}
从服务器接收数据的客户端代码:
void *recebe_msg(void *dados) {
int i;
sprintf(cli_fifo, "ccc%d", getpid());
mkfifo(cli_fifo, 0600);
fd_resp = open(cli_fifo, O_RDWR);
menu();
do {
i = read(fd_resp, &r, sizeof (r));
if (ESTADO == 0) {
if (r.cmd == 1 && r.res == 1) { // OK
ESTADO = 1;
wclear(win);
mvwprintw(win, 10, 14, "Login efectuado com sucesso!");
wprintw(win, "BONECO %d, %d , %d , %d ",r.b[0].num,r.b[0].humano,r.b[0].remate,r.b[0].tempo);
wrefresh(win);
sleep(3);
desenha_campo();
}
if (r.cmd == 1 && r.res == 0) { // NOK
wclear(win);
mvwprintw(win, 10, 14, "Senha e/ou login incorrectos!!!");
wrefresh(win);
sleep(3);
menu();
}
if (r.cmd == 2 && r.res == 0) {
wclear(win);
mvwprintw(win, 10, 14, "Login já está em uso!");
wrefresh(win);
sleep(3);
menu();
}
if (r.cmd == 2 && r.res == 1) {
wclear(win);
mvwprintw(win, 10, 14, "Registo efectuado com sucesso!");
wrefresh(win);
sleep(3);
menu();
}
if (r.cmd == 9) { // sair
FIM = 1;
}
} else if (ESTADO == 1 || ESTADO == 2) {
wclear(win3);
scrollok(win3, TRUE);
keypad(win3, TRUE);
noecho();
if (r.cmd == 3) { // actualizacao de jogadores
desenha_campo();
desenha_jogadores();
} else if (r.cmd == 9) { // sair
FIM = 1;
}
}
} while (!FIM);
close(fd_resp);
unlink(cli_fifo);
pthread_exit(0);
}
OBS:我认为错误发生在struct RESPOSTA的第3个字段上,但我不知道如何解决它
答案 0 :(得分:1)
在这里你读了BONECO结构:
i = read(fd_resp, &r, sizeof (r));
请注意,BONECO被声明为指针,而不是实际数据。
但是你在这里尝试阅读这些数据:
wprintw(win, "BONECO %d, %d , %d , %d ",r.b[0].num,r.b[0].humano,r.b[0].remate,r.b[0].tempo);
当您尝试访问r.b [0]时,您会出现分段错误,因为您尝试取消引用b指针,指向...未知位置。这会导致错误。
我建议将结构修改为:
typedef struct {
int cmd;
int res;
int count_of_boneco;
BONECO b[];
} RESPOSTA;
如果您分配了足够大的缓冲区,您可以阅读所有数据,然后立即取消引用。