Question

我的问题是代码是代码返回包括经理在内的员工的最高工资当我希望它排除经理时。

除此之外它还有效。

这是我写的代码：

SELECT firstname || ' ' || lastname 
AS "FULL NAME"
FROM EMPLOYEES
WHERE salary = 
    ( SELECT MAX(salary)
        FROM EMPLOYEES, DEPARTMENTS 
        WHERE NOT employee_id = manager_id);

这是数据库架构

COUNTRIES(country_id, country_name, region) 
• Primary key: {country_id}

DEPARTMENTS(department_id, department_name, manager_id)
• Primary key: {department_id }
• Foreign key: [manager_id]  ⊆ EMPLOYEES[employee_id]

DEPT_LOCATIONS(department_id, city, country_id)
• Primary key: {department_id, city}
• Foreign key: [department_id]  ⊆ DEPARTMENTS[department_id] and 
[country_id]  ⊆ COUNTRIES[country_id]

EMPLOYEES(employee_id, firstname, lastname, email, phone_no, salary, 
department_id)
• Primary key: {employee_id}
• Foreign key: [department_id]  ⊆ DEPARTMENTS[department_id]

任何帮助都非常感激。

Answer 1

如果您的子查询按部门选择最高工资，那么您可以加入该结果以按部门获取您的列表。

SELECT firstname || ' ' || lastname AS "FULL NAME",
       E.department_id
FROM EMPLOYEES E
JOIN (
  SELECT E.department_id, MAX(E.salary) as MAX_SALARY
  FROM EMPLOYEES E
  JOIN DEPARTMENTS D ON E.department_id = D.department_id
  WHERE employee_id <> manager_id
  GROUP BY E.department_id 
) AS M ON M.MAX_SALARY = E.salary AND E.department_id = M.department_id

如果您不按部门要求，它看起来像这样：

SELECT firstname || ' ' || lastname AS "FULL NAME"
FROM EMPLOYEES E
JOIN (
  SELECT MAX(E.salary) as MAX_SALARY
  FROM EMPLOYEES E
  JOIN DEPARTMENTS D ON E.department_id = D.department_id
  WHERE employee_id <> manager_id
) AS M ON M.MAX_SALARY = E.salary

Answer 2

这个怎么样？

SELECT e.firstname || ' ' || e.lastname 
AS "FULL NAME"
FROM EMPLOYEES e
WHERE e.salary = 
    ( SELECT MAX(salary)
        FROM EMPLOYEES, DEPARTMENTS 
        WHERE NOT employee_id = manager_id)
AND NOT EXISTS (SELECT 1 FROM DEPARTMENTS d WHERE e.employee_id = d.manager_id)

您只需过滤结果

SQL - SELECTING MAX返回不同的列

2 个答案: