Question

如何在每个循环中更改数组名称？

这是我的代码的简化版本：

if (POSITION1 == 1) {
    ArrayAdapter<String> mAdapter = new ArrayAdapter<String>(Main2Activity.this,
    R.layout.simple_list_item_single_choice_2,
    getResources().getStringArray(R.array.Électron_P));
    listView.setAdapter(mAdapter);
}

if (POSITION1 == 2) {
    ArrayAdapter<String> mAdapter = new ArrayAdapter<String>(Main2Activity.this,
    R.layout.simple_list_item_single_choice_2,
    getResources().getStringArray(R.array.Monstre_P));
    listView.setAdapter(mAdapter);
}

if (POSITION1 == 3) {
   ArrayAdapter<String> mAdapter = new ArrayAdapter<String>(Main2Activity.this,
   R.layout.simple_list_item_single_choice_2,
   getResources().getStringArray(R.array.Neutron_P));
   listView.setAdapter(mAdapter);
}

我想让它在单个循环中工作，但我不明白需要替换数组的名称

for (i = 0; i <= 3; i++) { 
    if (POSITION1 == i) {
        ArrayAdapter<String> mAdapter = new ArrayAdapter<String>(Main2Activity.this,
        R.layout.simple_list_item_single_choice_2,
        getResources().getStringArray(R.array.??????));
        listView.setAdapter(mAdapter);
    }
}

任何帮助将不胜感激！

Answer 1

我不理解您问题的循环部分，但您可以使用字典存储POSITION1的有效值

int[] options= new int[] {
    R.array.Électron_P,
    R.array.Monstre_P,
    R.array.Neutron_P
};

int resId = options[POSITION1 - 1];
ArrayAdapter<String> mAdapter = new ArrayAdapter<String>(Main2Activity.this,
            R.layout.simple_list_item_single_choice_2,
            getResources().getStringArray(resId));
listView.setAdapter(mAdapter);

Answer 2

你不能使用循环，试试这个：

    HashMap positions = new LinkedHashMap();

    positions.put(1,R.array.Électron_P);
    positions.put(2,R.array.Monstre_P);
    positions.put(3,R.array.Neutron_P);

    ArrayAdapter<String> mAdapter = new ArrayAdapter<String>(Main2Activity.this,
            R.layout.simple_list_item_single_choice_2,
            getResources().getStringArray(positions.get(POSITION1)));
    listView.setAdapter(mAdapter);

Answer 3

尝试使用开关简化

int selectedArray = 0;
switch(POSITION1) {
case 1:
    selectedArray = R.array.Électron_P;
    break;
case 2:
    selectedArray = R.array.Monstre_P;
    break;
case 3:
    selectedArray = R.array.Neutron_P;
    break;
}

ArrayAdapter<String> mAdapter = new ArrayAdapter<String>(Main2Activity.this,
        R.layout.simple_list_item_single_choice_2,
        getResources().getStringArray(selectedArray));
listView.setAdapter(mAdapter);

优化循环中数组的选择

3 个答案: