在spring mvc code

时间:2017-09-08 01:37:18

标签: spring-mvc

1.原始服务器没有找到目标资源的当前表示,或者不愿意透露是否存在。“我是SpringMVC的新手并且无法解决这个问题,请帮助我以便我可以移动转发学习这门课程。我尝试了我在网上得到的一切

  

的index.jsp

<%response.setHeader("Cache-Control","no-cache"); //HTTP 1.1
 response.setHeader("Pragma","no-cache"); //HTTP 1.0
 response.setDateHeader ("Expires", 0);
 %>
<html>
<body>
<form action="add">
    <input type="text" name="t1"><br>
    <input type="text" name="t2"><br>
    <input type="submit">
</form>
</body>
 </html>
  

第一servlet.xml中

 <beans xmlns="http://www.springframework.org/schema/beans"
     xmlns:ctx="http://www.springframework.org/schema/context"
     xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
     xmlns:mvc="http://www.springframework.org/schema/mvc"
     xsi:schemaLocation="http://www.springframework.org/schema/beans      
     http://www.springframework.org/schema/beans/spring-beans-2.5.xsd      
     http://www.springframework.org/schema/mvc      
     http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd
     http://www.springframework.org/schema/context
          http://www.springframework.org/schema/context/spring-context-2.5.xsd ">
     <ctx:annotation-config></ctx:annotation-config>
     <ctx:component-scan base-package="com.Tutorial"></ctx:component-scan>
     <mvc:annotation-driven></mvc:annotation-driven>
 </beans>
  

的web.xml

  <web-app>
   <display-name>Archetype Created Web Application</display-name>
   <servlet>
     <servlet-name>first</servlet-name>
     <servlet-class>
           org.springframework.web.servlet.DispatcherServlet
      </servlet-class>
     <load-on-startup>1</load-on-startup>
   </servlet>
  <servlet-mapping>
        <servlet-name>first</servlet-name>
         <url-pattern>/</url-pattern>
   </servlet-mapping>
 </web-app>
  

AddControllerTYpe.java

 package com.Tutorial.FirstWebProject;
 import org.springframework.stereotype.Controller;
 import org.springframework.web.bind.annotation.RequestMapping;
 @Controller
 public class AddControllerType 
 {
      @RequestMapping("/add")
     public void add()
     {  
         System.out.println("-----its here-----");
     }
 }

0 个答案:

没有答案