Question

我是hibernate的新手。我在MySQL中使用Hibernate来保存我的数据。这是我的实体类。

@Entity
@XmlRootElement
public class SecuredCustomer implements Serializable{

    @Id
    private String loginId;
    private String password;

    @Embedded
    UserInfo userInformation = new UserInfo();

    int allocatedRestaurantTableId;

    @Embedded
    Order order;

    @Embedded
    Bill bill;


    public SecuredCustomer(){
        allocatedRestaurantTableId = -1;
        order = null;
        bill = null;
    }

    public Bill getBill() {
        return bill;
    }


    public void setBill(Bill bill) {
        this.bill = bill;
    }


    public Order getOrder() {
        return order;
    }


    public void setOrder(Order order) {
        this.order = order;
    }


    public int getAllocatedRestaurantTableId() {
        return allocatedRestaurantTableId;
    }


    public void setAllocatedRestaurantTableId(int allocatedRestaurantTableId) {
        this.allocatedRestaurantTableId = allocatedRestaurantTableId;
    }

    public UserInfo getUserInformation() {
        return userInformation;
    }

    public void setUserInformation(UserInfo userInformation) {
        this.getUserInformation().setAddress(userInformation.getAddress());
        this.getUserInformation().setAge(userInformation.getAge());
        this.getUserInformation().setName(userInformation.getName());
        this.getUserInformation().setPhoneNumber(userInformation.getPhoneNumber());

    }

    public String getLoginId() {
        return loginId;
    }

    public void setLoginId(String loginId) {
        this.loginId = loginId;
    }

    public String getPassword() {
        return password;
    }

    public void setPassword(String password) {
        this.password = password;
    }

    @Override
    public boolean equals(Object obj)
    {
         return this == obj;
    }
}

当用户使用登录ID和密码注册时，我坚持使用此类。

现在我正在尝试检索如下数据：

SessionFactory sessionFactory = HibernateUtil.getSessionFactory();
                //Retrieving Data
                Session session = sessionFactory.openSession();
                session.beginTransaction();
                SecuredCustomer customerInDB = session.get(SecuredCustomer.class, userLoginId);

Hibernate创建的SQL如下： Hibernate：选择securedcus0_.loginId为loginId1_11_0_，securedcus0_.allocatedRestaurantTableId为allocate2_11_0_，securedcus0_.total为total3_11_0_，securedcus0_.password为password4_11_0_，securedcus0_.address为address5_11_0_，securedcus0_.age为age6_11_0_，securedcus0_.name为name7_11_0_，securedcus0_.phoneNumber为phoneNum8_11_0_来自SecuredCustomer securedcus0_，其中securedcus0_.loginId =？

此SQL语句正在运行并返回正确的值。

当我一步一步地调试时，它将从数据库返回数据。但是在eclipse / tomcat中运行相同的代码时，即使对象在DB的表中可用，它也会返回null对象。我在运行Ubuntu的localhost上测试webapp ... 请帮帮我。提前谢谢

Answer 1

解决了...创建了一个类

import javax.ws.rs.core.Response; 
import javax.ws.rs.ext.Provider;

@Provider
public class MoxyThrowable implements javax.ws.rs.ext.ExceptionMapper<Exception> {
    @Override
    public Response toResponse(Exception exception) {
        exception.printStackTrace();
        return Response.status(500).build();
    }
}

并查看详细错误。然后将一些相关的fetchtype更改为EAGER。它解决了问题......

在hibernate中的Session.get在逐步调试时工作，但在eclipse中运行时没有

1 个答案: