Question

相当有点困惑

我有一个格式化为

的文本文件

FooBoo，雄性，20,10 / 04/1988

我知道如何分割字符串，例如

public loadData() {  

   String filepath = "G:\\Documents\\MEMove\\XXClients\\data.txt";

    BufferedReader bufReader = new BufferedReader(new FileReader(filepath));

    String line = bufReader.readLine();

    while (line != null) {

        // String[] parts = line.split("/");
        String[] parts = line.split(",");
        String part1 = parts[0];
        String part2 = parts[1];

        int part3 = Integer.parseInt(parts[3]);
        String [] sDOB = line.split("/");
        int sDOB1 = Integer.parseInt(sDOB[4]);
        People nPeople = new People(part1,part2,part3,sDOB1);

       readPeopleList.add(nPeople);
        line = bufReader.readLine(); 
    } //end of while 
    bufReader.close();

    for(People per: readPeopleList)
    {
        System.out.println("Reading.." + per.getFullName());

    }
}// end of method

问题是如何拆分DOB /它不起作用我得到NumberFormatException错误

任何想法

谢谢

Answer 1

首先，使用分隔符","分割线：

String line = "FooBoo,male,20,10/04/1988";
String[] parts = line.split(",");

然后，使用分隔符"\"分割最后一部分：

String dob = parts[parts.length - 1];
String[] sDob = dob.split("/");
for (String s : sDob) {
    System.out.println(s);
}

修改：您可以将sDob转换为ArrayList，如下所示：

ArrayList<String> sDobList = new ArrayList<>(Arrays.asList(sDob));

从文本文件

1 个答案: