如何使用FETCH API将数据发送到spring引导方法

时间:2017-09-07 08:17:38

标签: javascript ajax spring spring-boot

我正在探索fetch api并希望将一些日期发送到spring引导方法,但是它会抛出400错误

JS代码

let fetchConfig = {
            method : params.method || 'GET',
            body : params.body
        };
        return fetch(_url,fetchConfig).then(function (response) {
            if (!response.ok) {
                throw Error(response.statusText);
            }
            else {
                return response.json();
            }
        }).then(function (data) {
            return data;
        }).catch(function (error) {
            return error;
        })

Spring引导方法

@RequestMapping(value = "/validate",method = RequestMethod.POST,produces = MediaType.APPLICATION_JSON_VALUE)
    public  @ResponseBody ValidateUserModel validateUser(@RequestParam("userName") String userName, @RequestParam("password") String pass){
        System.out.println("--- test");
        ValidateUserModel validateUserModel = new ValidateUserModel();
        validateUserModel.setUserName("Test");
        validateUserModel.setPassWord("Test 2");
        return  validateUserModel;
    }

这就是fetchConfig的样子

body:{userName: "awdaw", password: "awdawd"}
method:"POST"
password:"test"
url:"test"
userName:"awdaw"
__proto__:Object

预览从java类发送的值

error:"Bad Request"
exception:"org.springframework.web.bind.MissingServletRequestParameterException"
message:"Required String parameter 'userName' is not present"
path:"/validate"
status:400
timestamp:1504771336175

错误显示为Required String parameter 'userName' is not present,但fetchConfig具有所需的密钥

2 个答案:

答案 0 :(得分:0)

您的Java代码需要请求参数,因此预期的网址应该类似于.../validate?username=<someValue>&password=<otherValue>,但您的js是在正文中发送的(这是一个更好的选择,发送用户和密码作为URL的一部分是根本不安全。)

您可以将Java代码更改为

@RequestMapping(value = "/validate",method = RequestMethod.POST,produces = MediaType.APPLICATION_JSON_VALUE)
public  @ResponseBody ValidateUserModel validateUser(@RequestBody User user){
    System.out.println("--- test");
    ValidateUserModel validateUserModel = new ValidateUserModel();
    validateUserModel.setUserName(user.getUserName());
    validateUserModel.setPassWord(user.getPassword());
    return validateUserModel;
}

User只是一个以passworduserName为属性的bean。

答案 1 :(得分:0)

尝试使用@RequestBody注释。

@RequestMapping(value = "/validate",method = RequestMethod.POST,produces = MediaType.APPLICATION_JSON_VALUE)
public  @ResponseBody ValidateUserModel validateUser(@RequestBody User user){
    System.out.println("--- test");
    ValidateUserModel validateUserModel = new ValidateUserModel();
    validateUserModel.setUserName(user.getUserName());
    validateUserModel.setPassWord(user.getPassword());
    return validateUserModel;
}

,请求应如下所示:

  let data = {userName: "awdaw", password: "awdawd"};
    fetch{ url, {
      body: JSON.stringfy(data)
      method:"POST"
      headers: {
               "Content-Type": "application/json",
           },
     }).then(
            response =>  {
                return response.json();
            }